/usr/lib/mysql-testsuite/t/ps_10nestset.test is in mysql-testsuite-5.6 5.6.16-1~exp1.
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# #
# Prepared Statements test on #
# "nested sets" representing hierarchies #
# #
###############################################
# Source: http://kris.koehntopp.de/artikel/sql-self-references (dated 1999)
# Source: http://dbmsmag.com/9603d06.html (dated 1996)
--disable_warnings
drop table if exists t1;
--enable_warnings
# "Nested Set": This table represents an employee list with a hierarchy tree.
# The tree is not modeled by "parent" links but rather by showing the "left"
# and "right" border of any person's "region". By convention, "l" < "r".
# As it is a tree, these "regions" of two persons A and B are either disjoint,
# or A's region is completely contained in B's (B.l < A.l < A.r < B.r:
# B is A's boss), or vice versa.
# Any other overlaps violate the model. See the references for more info.
create table t1 (
id INTEGER AUTO_INCREMENT PRIMARY KEY,
emp CHAR(10) NOT NULL,
salary DECIMAL(6,2) NOT NULL,
l INTEGER NOT NULL,
r INTEGER NOT NULL);
prepare st_ins from 'insert into t1 set emp = ?, salary = ?, l = ?, r = ?';
# Initial employee list:
# Jerry ( Bert () Chuck ( Donna () Eddie () Fred () ) )
set @arg_nam= 'Jerry'; set @arg_sal= 1000; set @arg_l= 1; set @arg_r= 12;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Bert'; set @arg_sal= 900; set @arg_l= 2; set @arg_r= 3;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Chuck'; set @arg_sal= 900; set @arg_l= 4; set @arg_r= 11;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Donna'; set @arg_sal= 800; set @arg_l= 5; set @arg_r= 6;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Eddie'; set @arg_sal= 700; set @arg_l= 7; set @arg_r= 8;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Fred'; set @arg_sal= 600; set @arg_l= 9; set @arg_r= 10;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
select * from t1;
# Three successive raises, each one is 100 units for managers, 10 percent for others.
prepare st_raise_base from 'update t1 set salary = salary * ( 1 + ? ) where r - l = 1';
prepare st_raise_mgr from 'update t1 set salary = salary + ? where r - l > 1';
let $1= 3;
set @arg_percent= .10;
set @arg_amount= 100;
while ($1)
{
execute st_raise_base using @arg_percent;
execute st_raise_mgr using @arg_amount;
dec $1;
}
select * from t1;
# Now, increase salary to a multiple of 50 (checks for bug#6138)
prepare st_round from 'update t1 set salary = salary + ? - ( salary MOD ? )';
set @arg_round= 50;
execute st_round using @arg_round, @arg_round;
select * from t1;
drop table t1;
# End of 4.1 tests
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