/usr/include/wibble/grcal/grcal.h is in libwibble-dev 1.1-1.
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#ifndef WIBBLE_GRCAL_GRCAL_H
#define WIBBLE_GRCAL_GRCAL_H
/*
* Gregorian calendar functions
*
* Copyright (C) 2007--2008 Enrico Zini <enrico@debian.org>
*
* This library is free software; you can redistribute it and/or
* modify it under the terms of the GNU Lesser General Public
* License as published by the Free Software Foundation; either
* version 2.1 of the License, or (at your option) any later version.
*
* This library is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with this library; if not, write to the Free Software
* Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
*/
#include <string>
/**
* @file
*
* This header provides functions to handle Gregorian calendar dates and times.
*
* The data type used through the module to represent a date is an int[6],
* containing:
* \l year
* \l month (starting from 1)
* \l day of month (starting from 1)
* \l hour
* \l minute
* \l second
*
* The int[6] array does not need to be completely filled, and any value except
* for the year can be left missing, with the value of -1. However, if a
* value is set to -1, all the following values in the array must also be -1.
* For example, 'March 2008' can be represented as { 2008, 3, -1, -1, -1, -1 },
* but something like { 2008, 3, -1, 12, -1, -1 } is not a valid date, as there
* can only be the value -1 after the first -1.
*
* The date+time in the int[6] array is always stored in UTC: the module does
* not attempt to work with timezones or daylight saving.
*
* The full range of the Gregorian calendar is accepted, so years like 1789
* will work fine, although pay extra attention if you are comparing historical
* events of countries that adopted the Gregorian calendar in different times,
* like Russia or Greece.
*
* Some functions work with the time of day only: those functions will work
* with int[3] parameters. The time of the day can also have missing values,
* with the same rules as the int[6] dates: this is midday: { 12, -1, -1 }, but
* this is not valid: { 12, -1, 30 }. However, in the case of int[3] times the
* hour can also be missing, so { -1, -1, -1 } is a valid time.
*
* Some function represent the time as a single integer: that is intended to be
* the number of seconds after the start of the day. Therefore, midnight would
* be 0, and midday would be 43200 (12*3600).
*/
struct tm;
namespace wibble {
namespace grcal {
/**
* Functions that work with int[6] datetime values
*/
namespace date {
/**
* Fill in an int[6] with the UTC values for today (leaving the time of day elements to -1)
*/
void today(int* dst);
/// Fill in an int[6] with the UTC values for now
void now(int* dst);
/// Return the number of days in a month
int daysinmonth(int year, int month);
/// Return the number of days in a year
int daysinyear(int year);
/**
* Compute the day of Easter.
*
* The algorithm used is the Meeus/Jones/Butcher Gregorian algorithm described
* at http://en.wikipedia.org/wiki/Computus
*/
void easter(int year, int* month, int* day);
/**
* Make a copy of the datetime, filling in missing values with the lowest
* possible value they can have
*/
void lowerbound(const int* src, int* dst);
/**
* Fill in the missing values of a datetime with the lowest possible value they
* can have
*/
void lowerbound(int* val);
/**
* Make a copy of the datetime, filling in missing values with the highest
* possible value they can have
*/
void upperbound(const int* src, int* dst);
/**
* Fill in the missing values of a datetime with the highest possible value they
* can have
*/
void upperbound(int* val);
/**
* Normalise a datetime, in place.
*
* This function takes in input a datetime with no missing values, but some
* values can be arbitrarily out of range. The datetime will be normalised so
* that all the elements will be within range, and it will still represent the
* same instant.
*
* For example (remember that months and days start from 1, so a day of 0 means
* "last day of previous month"):
*
* \l normalise({2007, 0, 1, 0, 0, 0}) gives {2006, 12, 1, 0, 0, 0}
* \l normalise({2007, -11, 1, 0, 0, 0}) gives {2006, 1, 1, 0, 0, 0}
* \l normalise({2007, 1, -364, 0, 0, 0}) gives {2006, 1, 1, 0, 0, 0}
* \l normalise({2007, 1, 366, 0, 0, 0}) gives {2008, 1, 1, 0, 0, 0}
* \l normalise({2009, 1, -364, 0, 0, 0}) gives {2008, 1, 2, 0, 0, 0}, because
* 2008 is a leap year
* \l normalise({2008, 1, 1, 0, 0, -3600}) gives {2007, 12, 31, 23, 0, 0}
*/
void normalise(int* res);
/**
* Compute the number of seconds that elapsed from the beginning of the given
* year until the given datetime.
*
* It is assumed that year <= val[0]: giving a year greather than val[0] will
* give unpredictable results.
*/
long long int secondsfrom(int year, const int* val);
/**
* Give the duration in seconds of the interval between begin and end.
*
* The result can be negative if end is an earlier date than begin.
*/
long long int duration(const int* begin, const int* end);
/**
* Make a copy of \a date, with the time part taken from \a time.
*
* \note \a time is an int[3] time value;
*/
void mergetime(const int* date, const int* time, int* dst);
/**
* Replace the time part of \a date with the values from time.
*
* \note \a time is an int[3] time value;
*/
void mergetime(int* date, const int* time);
/**
* Copy the values from an int[6] datetime into a struct tm.
*/
void totm(const int* src, struct tm* dst);
/**
* Copy the values from a struct tm to the first \a count values of the int[6]
* \a dst.
*/
void fromtm(const struct tm& src, int* dst, int count = 6);
/**
* Convert a datetime to a string
*/
std::string tostring(const int* val);
}
/**
* Functions that work with int[3] time of day values
*/
namespace dtime {
/**
* Make a copy of the time, filling in missing values with the lowest
* possible value they can have
*/
void lowerbound(const int* src, int* dst);
/**
* Fill in the missing values of a time of day with the lowest possible value
* they can have
*/
void lowerbound(int* val);
/**
* Convert a time of day in second, filling the missing values with the lowest
* possible value they can have.
*/
int lowerbound_sec(const int* src);
/**
* Make a copy of the time, filling in missing values with the highest possible
* value they can have
*/
void upperbound(const int* src, int* dst);
/**
* Fill in the missing values of a time of day with the highest possible value
* they can have
*/
void upperbound(int* val);
/**
* Convert a time of day in second, filling the missing values with the highest
* possible value they can have.
*/
int upperbound_sec(const int* src);
/**
* Give the duration in seconds of the interval between the end of begin
* and the beginning of end.
*
* The result can be negative if end is an earlier time than begin.
*/
int duration(const int* begin, const int* end);
/**
* Format a time of day to a string
*/
std::string tostring(const int* val);
/**
* Format a time of day expressed in seconds to a string
*/
std::string tostring(int val);
}
}
}
// vim:set ts=4 sw=4:
#endif
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