/usr/share/acl2-8.0dfsg/induct.lisp is in acl2-source 8.0dfsg-1.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
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3422 3423 3424 3425 3426 3427 3428 3429 3430 3431 3432 3433 3434 3435 3436 3437 3438 3439 3440 3441 3442 3443 3444 3445 3446 3447 3448 3449 3450 3451 | ; ACL2 Version 8.0 -- A Computational Logic for Applicative Common Lisp
; Copyright (C) 2017, Regents of the University of Texas
; This version of ACL2 is a descendent of ACL2 Version 1.9, Copyright
; (C) 1997 Computational Logic, Inc. See the documentation topic NOTE-2-0.
; This program is free software; you can redistribute it and/or modify
; it under the terms of the LICENSE file distributed with ACL2.
; This program is distributed in the hope that it will be useful,
; but WITHOUT ANY WARRANTY; without even the implied warranty of
; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
; LICENSE for more details.
; Written by: Matt Kaufmann and J Strother Moore
; email: Kaufmann@cs.utexas.edu and Moore@cs.utexas.edu
; Department of Computer Science
; University of Texas at Austin
; Austin, TX 78712 U.S.A.
(in-package "ACL2")
(defun select-x-cl-set (cl-set induct-hint-val)
; This function produces the clause set we explore to collect
; induction candidates. The x in this name means "explore." If
; induct-hint-val is non-nil and non-t, we use the user-supplied
; induction hint value (which, if t means use cl-set); otherwise, we
; use cl-set.
(cond ((null induct-hint-val) cl-set)
((equal induct-hint-val *t*) cl-set)
(t (list (list induct-hint-val)))))
(defun unchangeables (formals args quick-block-info subset ans)
; We compute the set of all variable names occurring in args in
; unchanging measured formal positions. We accumulate the answer onto
; ans.
(cond ((null formals) ans)
((and (member-eq (car formals) subset)
(eq (car quick-block-info) 'unchanging))
(unchangeables (cdr formals) (cdr args) (cdr quick-block-info) subset
(all-vars1 (car args) ans)))
(t
(unchangeables (cdr formals) (cdr args) (cdr quick-block-info) subset
ans))))
(defun changeables (formals args quick-block-info subset ans)
; We compute the args in changing measured formal positions. We
; accumulate the answer onto ans.
(cond ((null formals) ans)
((and (member-eq (car formals) subset)
(not (eq (car quick-block-info) 'unchanging)))
(changeables (cdr formals) (cdr args) (cdr quick-block-info)
subset
(cons (car args) ans)))
(t
(changeables (cdr formals) (cdr args) (cdr quick-block-info)
subset
ans))))
(defun sound-induction-principle-mask1 (formals args quick-block-info
subset
unchangeables
changeables)
; See sound-induction-principle-mask.
(cond
((null formals) nil)
(t (let ((var (car formals))
(arg (car args))
(q (car quick-block-info)))
(mv-let (mask-ele new-unchangeables new-changeables)
(cond ((member-eq var subset)
(cond ((eq q 'unchanging)
(mv 'unchangeable unchangeables changeables))
(t (mv 'changeable unchangeables changeables))))
((and (variablep arg)
(eq q 'unchanging))
(cond ((member-eq arg changeables)
(mv nil unchangeables changeables))
(t (mv 'unchangeable
(add-to-set-eq arg unchangeables)
changeables))))
((and (variablep arg)
(not (member-eq arg changeables))
(not (member-eq arg unchangeables)))
(mv 'changeable
unchangeables
(cons arg changeables)))
(t (mv nil unchangeables changeables)))
(cons mask-ele
(sound-induction-principle-mask1 (cdr formals)
(cdr args)
(cdr quick-block-info)
subset
new-unchangeables
new-changeables)))))))
(defun sound-induction-principle-mask (term formals quick-block-info subset)
; Term is a call of some fn on some args. The formals and
; quick-block-info are those of fn, and subset is one of fn's measured
; subset (a subset of formals). We wish to determine, in the
; terminology of ACL, whether the induction applies to term. If so we
; return a mask indicating how to build the substitutions for the
; induction from args and the machine for fn. Otherwise we return
; nil.
; Let the changeables be those args that are in measured formal
; positions that sometimes change in the recursion. Let the
; unchangeables be all of the variables occurring in measured actuals
; that never change in recursion. The induction applies if
; changeables is a sequence of distinct variable names and has an
; empty intersection with unchangeables.
; If the induction is applicable then the substitutions should
; substitute for the changeables just as the recursion would, and hold
; each unchangeable fixed -- i.e., substitute each for itself. With
; such substitutions it is possible to prove the measure lemmas
; analogous to those proved when justification of subset was stored,
; except that the measure is obtained by instantiating the measure
; term used in the justification by the measured actuals in unchanging
; slots. Actual variables that are neither among the changeables or
; unchangeables may be substituted for arbitrarily.
; If the induction is applicable we return a mask with as many
; elements as there are args. For each arg the mask contains either
; 'changeable, 'unchangeable, or nil. 'Changeable means the arg
; should be instantiated as specified in the recursion. 'Unchangeable
; means each var in the actual should be held fixed. Nil means that
; the corresponding substitution pairs in the machine for the function
; should be ignored.
; Abstractly, this function builds the mask by first putting either
; 'changeable or 'unchangeable in each measured slot. It then fills
; in the remaining slots from the left so as to permit the actual to
; be instantiated or held fixed as desired by the recursion, provided
; that in so doing it does not permit substitutions for previously
; allocated actuals.
(let ((unchangeables
(unchangeables formals (fargs term) quick-block-info subset nil))
(changeables
(changeables formals (fargs term) quick-block-info subset nil)))
(cond ((or (not (no-duplicatesp-equal changeables))
(not (all-variablep changeables))
(intersectp-eq changeables unchangeables))
nil)
(t (sound-induction-principle-mask1 formals
(fargs term)
quick-block-info
subset
unchangeables
changeables)))))
(defrec candidate
(score controllers changed-vars unchangeable-vars
tests-and-alists-lst justification induction-term other-terms
xinduction-term xother-terms xancestry
ttree)
nil)
; This record is used to represent one of the plausible inductions that must be
; considered. The SCORE represents some fairly artificial estimation of how
; many terms in the conjecture want this induction. CONTROLLERS is the list of
; the controllers -- including unchanging controllers -- for all the inductions
; merged to form this one. The CHANGED-VARS is a list of all those variables
; that will be instantiated (non-identically) in some induction hypotheses.
; Thus, CHANGED-VARS include both variables that actually contribute to why
; some measure goes down and variables like accumulators that are just along
; for the ride. UNCHANGEABLE-VARS is a list of all those vars which may not be
; changed by any substitution if this induction is to be sound for the reasons
; specified. TESTS-AND-ALISTS-LST is a list of TESTS-AND-ALISTS which
; indicates the case analysis for the induction and how the various induction
; hypotheses are obtained via substitutions. JUSTIFICATION is the
; JUSTIFICATION that justifies this induction, and INDUCTION-TERM is the term
; that suggested this induction and from which you obtain the actuals to
; substitute into the template. OTHER-TERMS are the induction-terms of
; candidates that have been merged into this one for heuristic reasons.
; Because of induction rules we can think of some terms being aliases for
; others. We have to make a distinction between the terms in the conjecture
; that suggested an induction and the actual terms that suggested the
; induction. For example, if an induction rule maps (fn x y) to (recur x y),
; then (recur x y) will be the INDUCTION-TERM because it suggested the
; induction and we will, perhaps, have to recover its induction machine or
; quick block information to implement various heuristics. But we do not wish
; to report (recur x y) to the user, preferring instead to report (fn x y).
; Therefore, corresponding to INDUCTION-TERM and OTHER-TERMS we have
; XINDUCTION-TERM and XOTHER-TERMS, which are maintained in exactly the same
; way as their counterparts but which deal completely with the user-level view
; of the induction. In practice this means that we will initialize the
; XINDUCTION-TERM field of a candidate with the term from the conjecture,
; initialize the INDUCTION-TERM with its alias, and then merge the fields
; completely independently but analogously. XANCESTRY is a field maintained by
; merging to contain the user-level terms that caused us to change our
; tests-and-alists. (Some candidates may be flushed or merged into this one
; without changing it.)
; The ttree of a candidate contains 'LEMMA tags listing the :induction rules
; (if any) involved in the suggestion of the candidate.
(defun count-non-nils (lst)
(cond ((null lst) 0)
((car lst) (1+ (count-non-nils (cdr lst))))
(t (count-non-nils (cdr lst)))))
(defun controllers (formals args subset ans)
(cond ((null formals) ans)
((member (car formals) subset)
(controllers (cdr formals) (cdr args) subset
(all-vars1 (car args) ans)))
(t (controllers (cdr formals) (cdr args) subset ans))))
(defun changed/unchanged-vars (x args mask ans)
(cond ((null mask) ans)
((eq (car mask) x)
(changed/unchanged-vars x (cdr args) (cdr mask)
(all-vars1 (car args) ans)))
(t (changed/unchanged-vars x (cdr args) (cdr mask) ans))))
(defrec tests-and-alists (tests alists) nil)
(defun tests-and-alists/alist (alist args mask call-args)
; Alist is an alist that maps the formals of some fn to its actuals,
; args. Mask is a sound-induction-principle-mask indicating the args
; for which we will build substitution pairs. Call-args is the list of
; arguments to some recursive call of fn occurring in the induction
; machine for fn. We build an alist mapping the masked args to the
; instantiations (under alist) of the values in call-args.
(cond
((null mask) nil)
((null (car mask))
(tests-and-alists/alist alist (cdr args) (cdr mask) (cdr call-args)))
((eq (car mask) 'changeable)
(cons (cons (car args)
(sublis-var alist (car call-args)))
(tests-and-alists/alist alist
(cdr args)
(cdr mask)
(cdr call-args))))
(t (let ((vars (all-vars (car args))))
(append (pairlis$ vars vars)
(tests-and-alists/alist alist
(cdr args)
(cdr mask)
(cdr call-args)))))))
(defun tests-and-alists/alists (alist args mask calls)
; Alist is an alist that maps the formals of some fn to its actuals,
; args. Mask is a sound-induction-principle-mask indicating the args
; for which we will build substitution pairs. Calls is the list of
; calls for a given case of the induction machine. We build the alists
; from those calls.
(cond
((null calls) nil)
(t (cons (tests-and-alists/alist alist args mask (fargs (car calls)))
(tests-and-alists/alists alist args mask (cdr calls))))))
; The following record contains the tests leading to a collection of
; recursive calls at the end of a branch through a defun. In general,
; the calls may not be to the function being defuned but rather to
; some other function in the same mutually recursive clique, but in
; the context of induction we know that all the calls are to the same
; fn because we haven't implemented mutually recursive inductions yet.
; A list of these records constitute the induction machine for a function.
(defrec tests-and-calls (tests . calls) nil)
; The justification record contains a subset of the formals of the function
; under which it is stored. Only the subset, ruler-extenders, and subversive-p
; fields have semantic content! The other fields are the domain predicate, mp;
; the relation, rel, which is well-founded on mp objects; and the mp-measure
; term which has been proved to decrease in the recursion. The latter three
; fields are correct at the time the function is admitted, but note that they
; might all be local and hence have disappeared by the time these fields are
; read. Thus, we include them only for heuristic purposes, for example as used
; in community book books/workshops/2004/legato/support/generic-theories.lisp.
; A list of justification records is stored under each function symbol by the
; defun principle.
(defrec justification
(subset . ((subversive-p . (mp . rel))
(measure . ruler-extenders)))
nil)
(defun tests-and-alists (alist args mask tc)
; Alist is an alist that maps the formals of some fn to its actuals,
; args. Mask is a sound-induction-principle-mask indicating the args
; for which we will build substitution pairs. Tc is one of the
; tests-and-calls in the induction machine for the function. We make
; a tests-and-alists record containing the instantiated tests of tc
; and alists derived from the calls of tc.
(make tests-and-alists
:tests (sublis-var-lst alist (access tests-and-calls tc :tests))
:alists (tests-and-alists/alists alist
args
mask
(access tests-and-calls tc :calls))))
(defun tests-and-alists-lst (alist args mask machine)
; We build a list of tests-and-alists from machine, instantiating it
; with alist, which is a map from the formals of the function to the
; actuals, args. Mask is the sound-induction-principle-mask that
; indicates the args for which we substitute.
(cond
((null machine) nil)
(t (cons (tests-and-alists alist args mask (car machine))
(tests-and-alists-lst alist args mask (cdr machine))))))
(defun flesh-out-induction-principle (term formals justification mask machine
xterm ttree)
; Term is a call of some function the indicated formals and induction machine.
; Justification is its 'justification and mask is a sound-induction-
; principle-mask for the term. We build the induction candidate suggested by
; term.
(make candidate
:score
(/ (count-non-nils mask) (length mask))
:controllers
(controllers formals (fargs term)
(access justification justification :subset)
nil)
:changed-vars
(changed/unchanged-vars 'changeable (fargs term) mask nil)
:unchangeable-vars
(changed/unchanged-vars 'unchangeable (fargs term) mask nil)
:tests-and-alists-lst
(tests-and-alists-lst (pairlis$ formals (fargs term))
(fargs term) mask machine)
:justification justification
:induction-term term
:xinduction-term xterm
:other-terms nil
:xother-terms nil
:xancestry nil
:ttree ttree))
(defun intrinsic-suggested-induction-cand
(term formals quick-block-info justification machine xterm ttree ens wrld)
; Note: An "intrinsically suggested" induction scheme is an induction scheme
; suggested by a justification of a recursive function. The rune controlling
; the intrinsic suggestion from the justification of fn is (:induction fn). We
; distinguish between intrinsically suggested inductions and those suggested
; via records of induction-rule type. Intrinsic inductions have no embodiment
; as induction-rules but are, instead, the basis of the semantics of such
; rules. That is, the inductions suggested by (fn x y) is the union of those
; suggested by the terms to which it is linked via induction-rules together
; with the intrinsic suggestion for (fn x y).
; Term, above, is a call of some fn with the given formals, quick-block-info,
; justification and induction machine. We return a list of induction
; candidates, said list either being empty or the singleton list containing the
; induction candidate intrinsically suggested by term. Xterm is logically
; unrelated to term and is the term appearing in the original conjecture from
; which we (somehow) obtained term for consideration.
(let ((induction-rune (list :induction (ffn-symb term))))
(cond
((enabled-runep induction-rune ens wrld)
(let ((mask (sound-induction-principle-mask term formals
quick-block-info
(access justification
justification
:subset))))
(cond
(mask
(list (flesh-out-induction-principle term formals
justification
mask
machine
xterm
(push-lemma induction-rune
ttree))))
(t nil))))
(t nil))))
(defrec induction-rule (nume (pattern . condition) scheme . rune) nil)
(mutual-recursion
(defun apply-induction-rule (rule term type-alist xterm ttree seen ens wrld)
; We apply the induction-rule, rule, to term, and return a possibly empty list
; of suggested inductions. The basic idea is to check that the rule is enabled
; and that the :pattern of the rule matches term. If so, we check that the
; :condition of the rule is true under the current type-alist. This check is
; heuristic only and so we indicate that the guards have been checked and we
; allow forcing. We ignore the ttree because we are making a heuristic choice
; only. If type-set says the :condition is non-nil, we fire the rule by
; instantiating the :scheme and recursively getting the suggested inductions
; for that term. Note that we are not recursively exploring the instantiated
; scheme but just getting the inductions suggested by its top-level function
; symbol.
; Seen is a list of numes of induction-rules already encountered, used in order
; to prevent infinite loops. The following are two examples that looped before
; the use of this list of numes seen.
; From Daron Vroon:
; (defun zip1 (xs ys)
; (declare (xargs :measure (acl2-count xs)))
; (cond ((endp xs) nil)
; ((endp ys) nil)
; (t (cons (cons (car xs) (car ys)) (zip1 (cdr xs) (cdr ys))))))
; (defun zip2 (xs ys)
; (declare (xargs :measure (acl2-count ys)))
; (cond ((endp xs) nil)
; ((endp ys) nil)
; (t (cons (cons (car xs) (car ys)) (zip2 (cdr xs) (cdr ys))))))
; (defthm zip1-zip2-ind
; t
; :rule-classes ((:induction :pattern (zip1 xs ys)
; :scheme (zip2 xs ys))))
; (defthm zip2-zip1-ind
; t
; :rule-classes ((:induction :pattern (zip2 xs ys)
; :scheme (zip1 xs ys))))
; (defstub foo (*) => *)
; ;; the following overflows the stack.
; (thm
; (= (zip1 (foo xs) ys)
; (zip2 (foo xs) ys)))
; From Pete Manolios:
; (defun app (x y)
; (if (endp x)
; y
; (cons (car x) (app (cdr x) y))))
; (defthm app-ind
; t
; :rule-classes ((:induction :pattern (app x y)
; :condition (and (true-listp x) (true-listp y))
; :scheme (app x y))))
; (in-theory (disable (:induction app)))
; (defthm app-associative
; (implies (and (true-listp a)
; (true-listp b)
; (true-listp c))
; (equal (app (app a b) c)
; (app a (app b c)))))
(let ((nume (access induction-rule rule :nume)))
(cond
((and (not (member nume seen))
(enabled-numep nume ens))
(mv-let
(ans alist)
(one-way-unify (access induction-rule rule :pattern)
term)
(cond
(ans
(with-accumulated-persistence
(access induction-rule rule :rune)
(suggestions)
suggestions
(mv-let
(ts ttree1)
(type-set (sublis-var alist
(access induction-rule rule :condition))
t nil type-alist ens wrld nil nil nil)
(declare (ignore ttree1))
(cond
((ts-intersectp *ts-nil* ts) nil)
(t (let ((term1 (sublis-var alist
(access induction-rule rule :scheme))))
(cond ((or (variablep term1)
(fquotep term1))
nil)
(t (suggested-induction-cands term1 type-alist
xterm
(push-lemma
(access induction-rule
rule
:rune)
ttree)
(cons nume seen)
ens wrld)))))))))
(t nil))))
(t nil))))
(defun suggested-induction-cands1
(induction-rules term type-alist xterm ttree seen ens wrld)
; We map down induction-rules and apply each enabled rule to term, which is
; known to be an application of the function symbol fn to some args. Each rule
; gives us a possibly empty list of suggested inductions. We append all these
; suggestions together. In addition, if fn is recursively defined and is
; enabled (or, even if fn is disabled if we are exploring a user-supplied
; induction hint) we collect the intrinsic suggestion for term as well.
; Seen is a list of numes of induction-rules already encountered, used in order
; to prevent infinite loops.
(cond
((null induction-rules)
(let* ((fn (ffn-symb term))
(machine (getpropc fn 'induction-machine nil wrld)))
(cond
((null machine) nil)
(t
; Historical note: Before Version_2.6 we had the following note:
; Note: The intrinsic suggestion will be non-nil only if (:INDUCTION fn) is
; enabled and so here we have a case in which two runes have to be enabled
; (the :DEFINITION and the :INDUCTION runes) to get the desired effect. It
; is not clear if this is a good design but at first sight it seems to
; provide upward compatibility because in Nqthm a disabled function suggests
; no inductions.
; We no longer make any such requirement: the test above (t) replaces the
; following.
; (or (enabled-fnp fn nil ens wrld)
; (and induct-hint-val
; (not (equal induct-hint-val *t*))))
(intrinsic-suggested-induction-cand
term
(formals fn wrld)
(getpropc fn 'quick-block-info
'(:error "See SUGGESTED-INDUCTION-CANDS1.")
wrld)
(getpropc fn 'justification
'(:error "See SUGGESTED-INDUCTION-CANDS1.")
wrld)
machine
xterm
ttree
ens
wrld)))))
(t (append (apply-induction-rule (car induction-rules)
term type-alist
xterm ttree seen ens wrld)
(suggested-induction-cands1 (cdr induction-rules)
term type-alist
xterm ttree seen ens wrld)))))
(defun suggested-induction-cands
(term type-alist xterm ttree seen ens wrld)
; Term is some fn applied to args. Xterm is some term occurring in the
; conjecture we are exploring and is the term upon which this induction
; suggestion will be "blamed" and from which we have obtained term via
; induction-rules. We return all of the induction candidates suggested by
; term. Lambda applications suggest no inductions. Disabled functions suggest
; no inductions -- unless we are applying the user's induct hint value (in
; which case we, quite reasonably, assume every function in the value is worthy
; of analysis since any function could have been omitted).
; Seen is a list of numes of induction-rules already encountered, used in order
; to prevent infinite loops.
(cond
((flambdap (ffn-symb term)) nil)
(t (suggested-induction-cands1
(getpropc (ffn-symb term) 'induction-rules nil wrld)
term type-alist xterm ttree seen ens wrld))))
)
(mutual-recursion
(defun get-induction-cands (term type-alist ens wrld ans)
; We explore term and accumulate onto ans all of the induction
; candidates suggested by it.
(cond ((variablep term) ans)
((fquotep term) ans)
((eq (ffn-symb term) 'hide)
ans)
(t (get-induction-cands-lst
(fargs term)
type-alist ens wrld
(append (suggested-induction-cands term type-alist
term nil nil ens wrld)
ans)))))
(defun get-induction-cands-lst (lst type-alist ens wrld ans)
; We explore the list of terms, lst, and accumulate onto ans all of
; the induction candidates.
(cond ((null lst) ans)
(t (get-induction-cands
(car lst)
type-alist ens wrld
(get-induction-cands-lst
(cdr lst)
type-alist ens wrld ans)))))
)
(defun get-induction-cands-from-cl-set1 (cl-set ens oncep-override wrld state
ans)
; We explore cl-set and accumulate onto ans all of the induction
; candidates.
(cond
((null cl-set) ans)
(t (mv-let (contradictionp type-alist fc-pairs)
(forward-chain-top 'induct
(car cl-set) nil t
nil ; do-not-reconsiderp
wrld ens oncep-override state)
; We need a type-alist with which to compute induction aliases. It is of
; heuristic use only, so we may as well turn the force-flg on. We assume no
; contradiction is found. If by chance one is, then type-alist is nil, which
; is an acceptable type-alist.
(declare (ignore contradictionp fc-pairs))
(get-induction-cands-lst
(car cl-set)
type-alist ens wrld
(get-induction-cands-from-cl-set1 (cdr cl-set)
ens oncep-override wrld state
ans))))))
(defun get-induction-cands-from-cl-set (cl-set pspv wrld state)
; We explore cl-set and collect all induction candidates.
(let ((rcnst (access prove-spec-var pspv :rewrite-constant)))
(get-induction-cands-from-cl-set1 cl-set
(access rewrite-constant
rcnst
:current-enabled-structure)
(access rewrite-constant
rcnst
:oncep-override)
wrld
state
nil)))
; That completes the development of the code for exploring a clause set
; and gathering the induction candidates suggested.
; Section: Pigeon-Holep
; We next develop pigeon-holep, which tries to fit some "pigeons" into
; some "holes" using a function to determine the sense of the word
; "fit". Since ACL2 is first-order we can't pass arbitrary functions
; and hence we pass symbols and define our own special-purpose "apply"
; that interprets the particular symbols passed to calls of
; pigeon-holep.
; However, it turns out that the applications of pigeon-holep require
; passing functions that themselves call pigeon-holep. And so
; pigeon-holep-apply is mutually recursive with pigeon-holep (but only
; because the application functions use pigeon-holep).
(mutual-recursion
(defun pigeon-holep-apply (fn pigeon hole)
; See pigeon-holep for the problem and terminology. This function
; takes a symbol denoting a predicate and two arguments. It applies
; the predicate to the arguments. When the predicate holds we say
; the pigeon argument "fits" into the hole argument.
(case fn
(pair-fitp
; This predicate is applied to two pairs, each taken from two substitutions.
; We say (v1 . term1) (the "pigeon") fits into (v2 . term2) (the "hole")
; if v1 is v2 and term1 occurs in term2.
(and (eq (car pigeon) (car hole))
(occur (cdr pigeon) (cdr hole))))
(alist-fitp
; This predicate is applied to two substitutions. We say the pigeon
; alist fits into the hole alist if each pair of the pigeon fits into
; a pair of the hole and no pair of the hole is used more than once.
(pigeon-holep pigeon hole nil 'pair-fitp))
(tests-and-alists-fitp
; This predicate is applied to two tests-and-alists records. The
; first fits into the second if the tests of the first are a subset
; of those of the second and either they are both base cases (i.e., have
; no alists) or each substitution of the first fits into a substitution of
; the second, using no substitution of the second more than once.
(and (subsetp-equal (access tests-and-alists pigeon :tests)
(access tests-and-alists hole :tests))
(or (and (null (access tests-and-alists pigeon :alists))
(null (access tests-and-alists hole :alists)))
(pigeon-holep (access tests-and-alists pigeon :alists)
(access tests-and-alists hole :alists)
nil
'alist-fitp))))))
(defun pigeon-holep (pigeons holes filled-holes fn)
; Both pigeons and holes are lists of arbitrary objects. The holes
; are implicitly enumerated left-to-right from 0. Filled-holes is a
; list of the indices of holes we consider "filled." Fn is a
; predicate known to pigeon-holep-apply. If fn applied to a pigeon and
; a hole is non-nil, then we say the pigeon "fits" into the hole. We
; can only "put" a pigeon into a hole if the hole is unfilled and the
; pigeon fits. The act of putting the pigeon into the hole causes the
; hole to become filled. We return t iff it is possible to put each
; pigeon into a hole under these rules.
(cond
((null pigeons) t)
(t (pigeon-holep1 (car pigeons)
(cdr pigeons)
holes 0
holes filled-holes fn))))
(defun pigeon-holep1 (pigeon pigeons lst n holes filled-holes fn)
; Lst is a terminal sublist of holes, whose first element has index n.
; We map over lst looking for an unfilled hole h such that (a) we can
; put pigeon into h and (b) we can dispose of the rest of the pigeons
; after filling h.
(cond
((null lst) nil)
((member n filled-holes)
(pigeon-holep1 pigeon pigeons (cdr lst) (1+ n) holes filled-holes fn))
((and (pigeon-holep-apply fn pigeon (car lst))
(pigeon-holep pigeons holes
(cons n filled-holes)
fn))
t)
(t (pigeon-holep1 pigeon pigeons (cdr lst) (1+ n)
holes filled-holes fn))))
)
(defun flush-cand1-down-cand2 (cand1 cand2)
; This function takes two induction candidates and determines whether
; the first is subsumed by the second. If so, it constructs a new
; candidate that is logically equivalent (vis a vis the induction
; suggested) to the second but which now carries with it the weight
; and heuristic burdens of the first.
(cond
((and (subsetp-eq (access candidate cand1 :changed-vars)
(access candidate cand2 :changed-vars))
(subsetp-eq (access candidate cand1 :unchangeable-vars)
(access candidate cand2 :unchangeable-vars))
(pigeon-holep (access candidate cand1 :tests-and-alists-lst)
(access candidate cand2 :tests-and-alists-lst)
nil
'tests-and-alists-fitp))
(change candidate cand2
:score (+ (access candidate cand1 :score)
(access candidate cand2 :score))
:controllers (union-eq (access candidate cand1 :controllers)
(access candidate cand2 :controllers))
:other-terms (add-to-set-equal
(access candidate cand1 :induction-term)
(union-equal
(access candidate cand1 :other-terms)
(access candidate cand2 :other-terms)))
:xother-terms (add-to-set-equal
(access candidate cand1 :xinduction-term)
(union-equal
(access candidate cand1 :xother-terms)
(access candidate cand2 :xother-terms)))
:ttree (cons-tag-trees (access candidate cand1 :ttree)
(access candidate cand2 :ttree))))
(t nil)))
(defun flush-candidates (cand1 cand2)
; This function determines whether one of the two induction candidates
; given flushes down the other and if so returns the appropriate
; new candidate. This function is a mate and merge function used
; by m&m and is hence known to m&m-apply.
(or (flush-cand1-down-cand2 cand1 cand2)
(flush-cand1-down-cand2 cand2 cand1)))
; We now begin the development of the merging of two induction
; candidates. The basic idea is that if two functions both replace x
; by x', and one of them simultaneously replaces a by a' while the
; other replaces b by b', then we should consider inducting on x, a,
; and b, by x', a', and b'. Of course, by the time we get here, the
; recursion is coded into substitution alists: ((x . x') (a . a')) and
; ((x . x') (b . b')). We merge these two alists into ((x . x') (a .
; a') (b . b')). The merge of two sufficiently compatible alists is
; accomplished by just unioning them together.
; The key ideas are (1) recognizing when two alists are describing the
; "same" recursive step (i.e., they are both replacing x by x', where
; x is somehow a key variable); (2) observing that they do not
; explicitly disagree on what to do with the other variables.
(defun alists-agreep (alist1 alist2 vars)
; Two alists agree on vars iff for each var in vars the image of var under
; the first alist is equal to that under the second.
(cond ((null vars) t)
((equal (let ((temp (assoc-eq (car vars) alist1)))
(cond (temp (cdr temp))(t (car vars))))
(let ((temp (assoc-eq (car vars) alist2)))
(cond (temp (cdr temp))(t (car vars)))))
(alists-agreep alist1 alist2 (cdr vars)))
(t nil)))
(defun irreconcilable-alistsp (alist1 alist2)
; Two alists are irreconcilable iff there is a var v that they both
; explicitly map to different values. Put another way, there exists a
; v such that (v . a) is a member of alist1 and (v . b) is a member of
; alist2, where a and b are different. If two substitutions are
; reconcilable then their union is a substitution.
; We rely on the fact that this function return t or nil.
(cond ((null alist1) nil)
(t (let ((temp (assoc-eq (caar alist1) alist2)))
(cond ((null temp)
(irreconcilable-alistsp (cdr alist1) alist2))
((equal (cdar alist1) (cdr temp))
(irreconcilable-alistsp (cdr alist1) alist2))
(t t))))))
(defun affinity (aff alist1 alist2 vars)
; We say two alists that agree on vars but are irreconcilable are
; "antagonists". Two alists that agree on vars and are not irreconcilable
; are "mates".
; Aff is either 'antagonists or 'mates and denotes one of the two relations
; above. We return t iff the other args are in the given relation.
(and (alists-agreep alist1 alist2 vars)
(eq (irreconcilable-alistsp alist1 alist2)
(eq aff 'antagonists))))
(defun member-affinity (aff alist alist-lst vars)
; We determine if some member of alist-lst has the given affinity with alist.
(cond ((null alist-lst) nil)
((affinity aff alist (car alist-lst) vars)
t)
(t (member-affinity aff alist (cdr alist-lst) vars))))
(defun occur-affinity (aff alist lst vars)
; Lst is a list of tests-and-alists. We determine whether alist has
; the given affinity with some alist in lst. We call this occur
; because we are looking inside the elements of lst. But it is
; technically a misnomer because we don't look inside recursively; we
; treat lst as though it were a list of lists.
(cond
((null lst) nil)
((member-affinity aff alist
(access tests-and-alists (car lst) :alists)
vars)
t)
(t (occur-affinity aff alist (cdr lst) vars))))
(defun some-occur-affinity (aff alists lst vars)
; Lst is a list of tests-and-alists. We determine whether some alist
; in alists has the given affinity with some alist in lst.
(cond ((null alists) nil)
(t (or (occur-affinity aff (car alists) lst vars)
(some-occur-affinity aff (cdr alists) lst vars)))))
(defun all-occur-affinity (aff alists lst vars)
; Lst is a list of tests-and-alists. We determine whether every alist
; in alists has the given affinity with some alist in lst.
(cond ((null alists) t)
(t (and (occur-affinity aff (car alists) lst vars)
(all-occur-affinity aff (cdr alists) lst vars)))))
(defun contains-affinity (aff lst vars)
; We determine if two members of lst have the given affinity.
(cond ((null lst) nil)
((member-affinity aff (car lst) (cdr lst) vars) t)
(t (contains-affinity aff (cdr lst) vars))))
; So much for general-purpose scanners. We now develop the predicates
; that are used to determine if we can merge lst1 into lst2 on vars.
; See merge-tests-and-alists-lsts for extensive comments on the ideas
; behind the following functions.
(defun antagonistic-tests-and-alists-lstp (lst vars)
; Lst is a list of tests-and-alists. Consider just the set of all
; alists in lst. We return t iff that set contains an antagonistic
; pair.
; We operate as follows. Each element of lst contains some alists.
; We take the first element and ask whether its alists contain an
; antagonistic pair. If so, we're done. Otherwise, we ask whether
; any alist in that first element is antagonistic with the alists in
; the rest of lst. If so, we're done. Otherwise, we recursively
; look at the rest of lst.
(cond
((null lst) nil)
(t (or (contains-affinity
'antagonists
(access tests-and-alists (car lst) :alists)
vars)
(some-occur-affinity
'antagonists
(access tests-and-alists (car lst) :alists)
(cdr lst)
vars)
(antagonistic-tests-and-alists-lstp (cdr lst) vars)))))
(defun antagonistic-tests-and-alists-lstsp (lst1 lst2 vars)
; Both lst1 and lst2 are lists of tests-and-alists. We determine whether
; there exists an alist1 in lst1 and an alist2 in lst2 such that alist1
; and alist2 are antagonists.
(cond
((null lst1) nil)
(t (or (some-occur-affinity
'antagonists
(access tests-and-alists (car lst1) :alists)
lst2
vars)
(antagonistic-tests-and-alists-lstsp (cdr lst1) lst2 vars)))))
(defun every-alist1-matedp (lst1 lst2 vars)
; Both lst1 and lst2 are lists of tests-and-alists. We determine for every
; alist1 in lst1 there exists an alist2 in lst2 that agrees with alist1 on
; vars and that is not irreconcilable.
(cond ((null lst1) t)
(t (and (all-occur-affinity
'mates
(access tests-and-alists (car lst1) :alists)
lst2
vars)
(every-alist1-matedp (cdr lst1) lst2 vars)))))
; The functions above are used to determine that lst1 and lst2 contain
; no antagonistic pairs, that every alist in lst1 has a mate somewhere in
; lst2, and that the process of merging alists from lst1 with their
; mates will not produce alists that are antagonistic with other alists
; in lst1. We now develop the code for merging non-antagonistic alists
; and work up the structural hierarchy to merging lists of tests and alists.
(defun merge-alist1-into-alist2 (alist1 alist2 vars)
; We assume alist1 and alist2 are not antagonists. Thus, either they
; agree on vars and have no explicit disagreements, or they simply
; don't agree on vars. If they agree on vars, we merge alist1 into
; alist2 by just unioning them together. If they don't agree on vars,
; then we merge alist1 into alist2 by ignoring alist1.
(cond
((alists-agreep alist1 alist2 vars)
(union-equal alist1 alist2))
(t alist2)))
; Now we begin working up the structural hierarchy. Our strategy is
; to focus on a given alist2 and hit it with every alist1 we have.
; Then we'll use that to copy lst2 once, hitting each alist2 in it
; with everything we have. We could decompose the problem the other
; way: hit lst2 with successive alist1's. That suffers from forcing
; us to copy lst2 repeatedly, and there are parts of that structure
; (i.e., the :tests) that don't change.
(defun merge-alist1-lst-into-alist2 (alist1-lst alist2 vars)
; Alist1-lst is a list of alists and alist2 is an alist. We know that
; there is no antagonists between the elements of alist1-lst and in
; alist2. We merge each alist1 into alist2 and return
; the resulting extension of alist2.
(cond
((null alist1-lst) alist2)
(t (merge-alist1-lst-into-alist2
(cdr alist1-lst)
(merge-alist1-into-alist2 (car alist1-lst) alist2 vars)
vars))))
(defun merge-lst1-into-alist2 (lst1 alist2 vars)
; Given a list of tests-and-alists, lst1, and an alist2, we hit alist2
; with every alist1 in lst1.
(cond ((null lst1) alist2)
(t (merge-lst1-into-alist2
(cdr lst1)
(merge-alist1-lst-into-alist2
(access tests-and-alists (car lst1) :alists)
alist2
vars)
vars))))
; So now we write the code to copy lst2, hitting each alist in it with lst1.
(defun merge-lst1-into-alist2-lst (lst1 alist2-lst vars)
(cond ((null alist2-lst) nil)
(t (cons (merge-lst1-into-alist2 lst1 (car alist2-lst) vars)
(merge-lst1-into-alist2-lst lst1 (cdr alist2-lst) vars)))))
(defun merge-lst1-into-lst2 (lst1 lst2 vars)
(cond ((null lst2) nil)
(t (cons (change tests-and-alists (car lst2)
:alists
(merge-lst1-into-alist2-lst
lst1
(access tests-and-alists (car lst2) :alists)
vars))
(merge-lst1-into-lst2 lst1 (cdr lst2) vars)))))
(defun merge-tests-and-alists-lsts (lst1 lst2 vars)
; Lst1 and lst2 are each tests-and-alists-lsts from some induction
; candidates. Intuitively, we try to stuff the alists of lst1 into
; those of lst2 to construct a new lst2 that combines the induction
; schemes of both. If we fail we return nil. Otherwise we return the
; modified lst2. The modified lst2 has exactly the same tests as
; before; only its alists are different and they are different only by
; virtue of having been extended with some addition pairs. So the
; justification of the merged induction is the same as the
; justification of the original lst2.
; Given an alist1 from lst1, which alist2's of lst2 do you extend and
; how? Suppose alist1 maps x to x' and y to y'. Then intuitively we
; think "the first candidate is trying to keep x and y in step, so
; that when x goes to x' y goes to y'." So, if you see an alist in
; lst2 that is replacing x by x', one might be tempted to augment it
; by replacing y by y'. However, what if x is just an accumulator?
; The role of vars is to specify upon which variables two
; substitutions must agree in order to be merged. Usually, vars
; consists of the measured variables.
; So now we get a little more technical. We will try to "merge" each
; alist1 from lst1 into each alist2 from lst2 (preserving the case structure
; of lst2). If alist1 and alist2 do not agree on vars then their merge
; is just alist2. If they do agree on vars, then their merge is their
; union, provided that is a substitution. It may fail to be a substitution
; because the two alists disagree on some other variable. In that case
; we say the two are irreconcilable. We now give three simple examples:
; Let vars be {x}. Let alist2 be {(x . x') (z . z')}. If alist1 maps
; x to x'', then their merge is just alist2 because alist1 is
; addressing a different case of the induction. If alist1 maps x to x'
; and y to y', then their merge is {(x . x') (y . y') (z . z')}. If
; alist1 maps x to x' and z to z'', then the two are irreconcilable.
; Two irreconcilable alists that agree on vars are called "antagonists"
; because they "want" to merge but can't. We cannot merge lst1 into lst2
; if they have an antagonistic pair between them. If an antagonistic pair
; is discovered, the entire merge operation fails.
; Now we will successively consider each alist1 in lst1 and merge it
; into lst2, forming successive lst2's. We insist that each alist1 of
; lst1 have at least one mate in lst2 with which it agrees and is
; reconcilable. (Otherwise, we could merge completely disjoint
; substitutions.)
; Because we try the alist1's successively, each alist1 is actually
; merged into the lst2 produced by all the previous alist1's. That
; produces an apparent order dependence. However, this is avoided by
; the requirement that we never produce antagonistic pairs.
; For example, suppose that in one case of lst1, x is mapped to x' and
; y is mapped to y', but in another case x is mapped to x' and y is
; mapped to y''. Now imagine trying to merge that lst1 into a lst2 in
; which x is mapped to x' and z is mapped to z'. The first alist of
; lst1 extends lst2 to (((x . x') (y . y') (z . z'))). But the second
; alist is then antagonistic. The same thing happens if we tried the two
; alists of lst1 in the other order. Thus, the above lst1 cannot be merged
; into lst2. Note that they can be merged in the other order! That is,
; lst2 can be merged into lst1, because the case structure of lst1 is
; richer.
; We can detect the situation above without forming the intermediate
; lst2. In particular, if lst1 contains an antagonistic pair, then it
; cannot be merged with any lst2 and we can quit.
; Note: Once upon a time, indeed, for the first 20 years or so of the
; existence of the merge routine, we took the attitude that if
; irreconcilable but agreeable alists arose, then we just added to
; alist2 those pairs of alist1 that were reconcilable and we left out
; the irreconcilable pairs. This however resulted in the system often
; merging complicated accumulator using functions (like TAUTOLOGYP)
; into simpler functions (like NORMALIZEDP) by dropping the
; accumulators that got in the way. This idea of just not doing
; "hostile merges" is being tried out for the first time in ACL2.
(cond ((antagonistic-tests-and-alists-lstp lst1 vars) nil)
((antagonistic-tests-and-alists-lstsp lst1 lst2 vars) nil)
((not (every-alist1-matedp lst1 lst2 vars)) nil)
(t (merge-lst1-into-lst2 lst1 lst2 vars))))
(defun merge-cand1-into-cand2 (cand1 cand2)
; Can induction candidate cand1 be merged into cand2? If so, return
; their merge. The guts of this function is merge-tests-and-alists-
; lsts. The tests preceding it are heuristic only. If
; merge-tests-and-alists-lsts returns non-nil, then it returns a sound
; induction; indeed, it merely extends some of the substitutions in
; the second candidate.
(let ((vars (or (intersection-eq
(access candidate cand1 :controllers)
(intersection-eq
(access candidate cand2 :controllers)
(intersection-eq
(access candidate cand1 :changed-vars)
(access candidate cand2 :changed-vars))))
(intersection-eq
(access candidate cand1 :changed-vars)
(access candidate cand2 :changed-vars)))))
; Historical Plaque from Nqthm:
; We once merged only if both cands agreed on the intersection of the
; changed-vars. But the theorem that, under suitable conditions, (EV
; FLG X VA FA N) = (EV FLG X VA FA K) made us realize it was important
; only to agree on the intersection of the controllers. Note in fact
; that we mean the changing controllers -- there seems to be no need
; to merge two inductions if they only share unchanging controllers.
; However the theorem that (GET I (SET J VAL MEM)) = ... (GET I MEM)
; ... illustrates the situation in which the controllers, {I} and {J}
; do not even overlap; but the accumulators {MEM} do and we want a
; merge. So we want agreement on the intersection of the changing
; controllers (if that is nonempty) or on the accumulators.
; For soundness it does not matter what list of vars we want to agree
; on because no matter what, merge-tests-and-alists-lsts returns
; either nil or an extension of the second candidate's alists.
(cond
((and vars
(not (intersectp-eq (access candidate cand1 :unchangeable-vars)
(access candidate cand2 :changed-vars)))
(not (intersectp-eq (access candidate cand2 :unchangeable-vars)
(access candidate cand1 :changed-vars))))
(let ((temp (merge-tests-and-alists-lsts
(access candidate cand1 :tests-and-alists-lst)
(access candidate cand2 :tests-and-alists-lst)
vars)))
(cond (temp
(make candidate
:score (+ (access candidate cand1 :score)
(access candidate cand2 :score))
:controllers (union-eq
(access candidate cand1 :controllers)
(access candidate cand2 :controllers))
:changed-vars (union-eq
(access candidate cand1 :changed-vars)
(access candidate cand2 :changed-vars))
:unchangeable-vars (union-eq
(access candidate cand1
:unchangeable-vars)
(access candidate cand2
:unchangeable-vars))
:tests-and-alists-lst temp
:justification (access candidate cand2 :justification)
:induction-term (access candidate cand2 :induction-term)
:other-terms (add-to-set-equal
(access candidate cand1 :induction-term)
(union-equal
(access candidate cand1 :other-terms)
(access candidate cand2 :other-terms)))
:xinduction-term (access candidate cand2 :xinduction-term)
:xother-terms (add-to-set-equal
(access candidate cand1 :xinduction-term)
(union-equal
(access candidate cand1 :xother-terms)
(access candidate cand2 :xother-terms)))
:xancestry (cond
((equal temp
(access candidate cand2
:tests-and-alists-lst))
(access candidate cand2 :xancestry))
(t (add-to-set-equal
(access candidate cand1 :xinduction-term)
(union-equal
(access candidate cand1 :xancestry)
(access candidate cand2 :xancestry)))))
; Note that :xancestry, computed just above, may not reflect cand1, but we
; always include the :ttree of cand1 just below. This is deliberate, since
; cand1 is contributing to the :score, and hence the eventual induction scheme
; chosen; so we want to report its induction rules in the final proof.
:ttree (cons-tag-trees (access candidate cand1 :ttree)
(access candidate cand2 :ttree))))
(t nil))))
(t nil))))
(defun merge-candidates (cand1 cand2)
; This function determines whether one of the two induction candidates
; can be merged into the other. If so, it returns their merge. This
; function is a mate and merge function used by m&m and is hence known
; to m&m-apply.
(or (merge-cand1-into-cand2 cand1 cand2)
(merge-cand1-into-cand2 cand2 cand1)))
; We now move from merging to flawing. The idea is to determine which
; inductions get in the way of others.
(defun controller-variables1 (args controller-pocket)
; Controller-pocket is a list of t's and nil's in 1:1 correspondence with
; args, indicating which args are controllers. We collect those controller
; args that are variable symbols.
(cond ((null controller-pocket) nil)
((and (car controller-pocket)
(variablep (car args)))
(add-to-set-eq (car args)
(controller-variables1 (cdr args)
(cdr controller-pocket))))
(t (controller-variables1 (cdr args)
(cdr controller-pocket)))))
(defun controller-variables (term controller-alist)
; Controller-alist comes from the def-body of the function symbol, fn, of term.
; Recall that controller-alist is an alist that associates with each function
; in fn's mutually recursive clique the controller pockets used in a given
; justification of the clique. In induction, as things stand today, we know
; that fn is singly recursive because we don't know how to handle mutual
; recursion yet. But no use is made of that here. We collect all the
; variables in controller slots of term.
(controller-variables1 (fargs term)
(cdr (assoc-eq (ffn-symb term)
controller-alist))))
(defun induct-vars1 (lst wrld)
; Lst is a list of terms. We collect every variable symbol occurring in a
; controller slot of any term in lst.
(cond ((null lst) nil)
(t (union-eq
(controller-variables
(car lst)
(access def-body
(def-body (ffn-symb (car lst)) wrld)
:controller-alist))
(induct-vars1 (cdr lst) wrld)))))
(defun induct-vars (cand wrld)
; Historical Plaque from Nqthm:
; Get all skos occupying controller slots in any of the terms associated
; with this candidate.
; The age of that comment is not known, but the fact that we referred
; to the variables as "skos" (Skolem constants) suggests that it may
; date from the Interlisp version. Meta comment: Perhaps someday some
; enterprising PhD student (in History?) will invent Software
; Archaeology, in which decrepit fragments of archive tapes are pieced
; together and scrutinized for clues as to the way people thought back
; in the early days.
(induct-vars1 (cons (access candidate cand :induction-term)
(access candidate cand :other-terms))
wrld))
(defun vetoedp (cand vars lst changed-vars-flg)
; Vars is a list of variables. We return t iff there exists a candidate
; in lst, other than cand, whose unchangeable-vars (or, if changed-vars-flg,
; changed-vars or unchangeable-vars) intersect with vars.
; This function is used both by compute-vetoes1, where flg is t and
; vars is the list of changing induction vars of cand, and by
; compute-vetoes2, where flg is nil and vars is the list of
; changed-vars cand. We combine these two into one function simply to
; eliminate a definition from the system.
(cond ((null lst) nil)
((equal cand (car lst))
(vetoedp cand vars (cdr lst) changed-vars-flg))
((and changed-vars-flg
(intersectp-eq vars
(access candidate (car lst) :changed-vars)))
t)
((intersectp-eq vars
(access candidate (car lst) :unchangeable-vars))
t)
(t (vetoedp cand vars (cdr lst) changed-vars-flg))))
(defun compute-vetoes1 (lst cand-lst wrld)
; Lst is a tail of cand-lst. We throw out from lst any candidate
; whose changing induct-vars intersect the changing or unchanging vars
; of another candidate in cand-lst. We assume no two elements of
; cand-lst are equal, an invariant assured by the fact that we have
; done merging and flushing before this.
(cond ((null lst) nil)
((vetoedp (car lst)
(intersection-eq
(access candidate (car lst) :changed-vars)
(induct-vars (car lst) wrld))
cand-lst
t)
(compute-vetoes1 (cdr lst) cand-lst wrld))
(t (cons (car lst)
(compute-vetoes1 (cdr lst) cand-lst wrld)))))
; If the first veto computation throws out all candidates, we revert to
; another heuristic.
(defun compute-vetoes2 (lst cand-lst)
; Lst is a tail of cand-lst. We throw out from lst any candidate
; whose changed-vars intersect the unchangeable-vars of another
; candidate in cand-lst. Again, we assume no two elements of cand-lst
; are equal.
(cond ((null lst) nil)
((vetoedp (car lst)
(access candidate (car lst) :changed-vars)
cand-lst
nil)
(compute-vetoes2 (cdr lst) cand-lst))
(t (cons (car lst)
(compute-vetoes2 (cdr lst) cand-lst)))))
(defun compute-vetoes (cand-lst wrld)
; We try two different techniques for throwing out candidates. If the
; first throws out everything, we try the second. If the second throws
; out everything, we throw out nothing.
; The two are: (1) throw out a candidate if its changing induct-vars
; (the variables in control slots that change) intersect with either
; the changed-vars or the unchangeable-vars of another candidate. (2)
; throw out a candidate if its changed-vars intersect the
; unchangeable-vars of another candidate.
; Historical Plaque from Nqthm:
; This function weeds out "unclean" induction candidates. The
; intuition behind the notion "clean" is that an induction is clean
; if nobody is competing with it for instantiation of its variables.
; What we actually do is throw out any candidate whose changing
; induction variables -- that is the induction variables as computed
; by induct-vars intersected with the changed vars of candidate --
; intersect the changed or unchanged variables of another candidate.
; The reason we do not care about the first candidates unchanging
; vars is as follows. The reason you want a candidate clean is so
; that the terms riding on that cand will reoccur in both the
; hypothesis and conclusion of an induction. There are two ways to
; assure (or at least make likely) this: change the variables in the
; terms as specified or leave them constant. Thus, if the first
; cand's changing vars are clean but its unchanging vars intersect
; another cand it means that the first cand is keeping those other
; terms constant, which is fine. (Note that the first cand would be
; clean here. The second might be clean or dirty depending on
; whether its changed vars or unchanged vars intersected the first
; cand's vars.) The reason we check only the induction vars and not
; all of the changed vars is if cand1's changed vars include some
; induction vars and some accumulators and the accumulators are
; claimed by another cand2 we believe that cand1 is still clean.
; The motivating example was
; (IMPLIES (MEMBER A C) (MEMBER A (UNION1 B C)))
; where the induction on C is dirty because the induction on B and C
; claims C, but the induction on B and C is clean because the B does
; not occur in the C induction. We do not even bother to check the
; C from the (B C) induction because since it is necessarily an
; accumulator it is probably being constructed and thus, if it
; occurs in somebody else's ind vars it is probably being eaten so
; it will be ok. In formulating this heuristic we did not consider
; the possibility that the accums of one candidate occur as
; constants in the other. Oh well.
; July 20, 1978. We have added an additional heuristic, to be
; applied if the above one eliminates all cands. We consider a cand
; flawed if it changes anyone else's constants. The motivating
; example was GREATEST-FACTOR-LESSP -- which was previously proved
; only by virtue of a very ugly use of the no-op fn ID to make a
; certain induction flawed.
(or (compute-vetoes1 cand-lst cand-lst wrld)
(compute-vetoes2 cand-lst cand-lst)
cand-lst))
; The next heuristic is to select complicated candidates, based on
; support for non-primitive recursive function schemas.
(defun induction-complexity1 (lst wrld)
; The "function" induction-complexity does not exist. It is a symbol
; passed to maximal-elements-apply which calls this function on the list
; of terms supported by an induction candidate. We count the number of
; non pr fns supported.
(cond ((null lst) 0)
((getpropc (ffn-symb (car lst)) 'primitive-recursive-defunp nil wrld)
(induction-complexity1 (cdr lst) wrld))
(t (1+ (induction-complexity1 (cdr lst) wrld)))))
; We develop a general-purpose function for selecting maximal elements from
; a list under a measure. That function, maximal-elements, is then used
; with the induction-complexity measure to collect both the most complex
; inductions and then to select those with the highest scores.
(defun maximal-elements-apply (fn x wrld)
; This function must produce an integerp. This is just the apply function
; for maximal-elements.
(case fn
(induction-complexity
(induction-complexity1 (cons (access candidate x :induction-term)
(access candidate x :other-terms))
wrld))
(score (access candidate x :score))
(otherwise 0)))
(defun maximal-elements1 (lst winners maximum fn wrld)
; We are scanning down lst collecting into winners all those elements
; with maximal scores as computed by fn. Maximum is the maximal score seen
; so far and winners is the list of all the elements passed so far with
; that score.
(cond ((null lst) winners)
(t (let ((temp (maximal-elements-apply fn (car lst) wrld)))
(cond ((> temp maximum)
(maximal-elements1 (cdr lst)
(list (car lst))
temp fn wrld))
; PETE
; In other versions the = below is, mistakenly, an int=!
((= temp maximum)
(maximal-elements1 (cdr lst)
(cons (car lst) winners)
maximum fn wrld))
(t
(maximal-elements1 (cdr lst)
winners
maximum fn wrld)))))))
(defun maximal-elements (lst fn wrld)
; Return the subset of lst that have the highest score as computed by
; fn. The functional parameter fn must be known to maximal-elements-apply.
; We reverse the accumulated elements to preserve the order used by
; nqthm.
(cond ((null lst) nil)
((null (cdr lst)) lst)
(t (reverse
(maximal-elements1 (cdr lst)
(list (car lst))
(maximal-elements-apply fn (car lst) wrld)
fn wrld)))))
; All that is left in the heuristic selection of the induction candidate is
; the function m&m that mates and merges arbitrary objects. We develop that
; now.
; The following three functions are not part of induction but are
; used by other callers of m&m and so have to be introduced now
; so we can define m&m-apply and get on with induct.
(defun intersectp-eq/union-equal (x y)
(cond ((intersectp-eq (car x) (car y))
(cons (union-eq (car x) (car y))
(union-equal (cdr x) (cdr y))))
(t nil)))
(defun equal/union-equal (x y)
(cond ((equal (car x) (car y))
(cons (car x)
(union-equal (cdr x) (cdr y))))
(t nil)))
(defun subsetp-equal/smaller (x y)
(cond ((subsetp-equal x y) x)
((subsetp-equal y x) y)
(t nil)))
(defun m&m-apply (fn x y)
; This is a first-order function that really just applies fn to x and
; y, but does so only for a fixed set of fns. In fact, this function
; handles exactly those functions that we give to m&m.
(case fn
(intersectp-eq/union-equal (intersectp-eq/union-equal x y))
(equal/union-equal (equal/union-equal x y))
(flush-candidates (flush-candidates x y))
(merge-candidates (merge-candidates x y))
(subsetp-equal/smaller (subsetp-equal/smaller x y))))
(defun count-off (n lst)
; Pair the elements of lst with successive integers starting at n.
(cond ((null lst) nil)
(t (cons (cons n (car lst))
(count-off (1+ n) (cdr lst))))))
(defun m&m-search (x y-lst del fn)
; Y-lst is a list of pairs, (id . y). The ids are integers. If id is
; a member of del, we think of y as "deleted" from y-lst. That is,
; y-lst and del together characterize a list of precisely those y such
; that (id . y) is in y-lst and id is not in del.
; We search y-lst for the first y that is not deleted and that mates
; with x. We return two values, the merge of x and y and the integer
; id of y. If no such y exists, return two nils.
(cond ((null y-lst) (mv nil nil))
((member (caar y-lst) del)
(m&m-search x (cdr y-lst) del fn))
(t (let ((z (m&m-apply fn x (cdar y-lst))))
(cond (z (mv z (caar y-lst)))
(t (m&m-search x (cdr y-lst) del fn)))))))
(defun m&m1 (pairs del ans n fn)
; This is workhorse for m&m. See that fn for a general description of
; the problem and the terminology. Pairs is a list of pairs. The car
; of each pair is an integer and the cdr is a possible element of the
; bag we are closing under fn. Del is a list of the integers
; identifying all the elements of pairs that have already been
; deleted. Abstractly, pairs and del together represent a bag we call
; the "unprocessed bag". The elements of the unprocessed bag are
; precisely those ele such that (i . ele) is in pairs and i is not in
; del.
; Without assuming any properties of fn, this function can be
; specified as follows: If the first element, x, of the unprocessed
; bag, mates with some y in the rest of the unprocessed bag, then put
; the merge of x and the first such y in place of x, delete that y,
; and iterate. If the first element has no such mate, put it in the
; answer accumulator ans. N, by the way, is the next available unique
; identifier integer.
; If one is willing to make the assumptions that the mate and merge
; fns of fn are associative and commutative and have the distributive
; and non-preclusion properties, then it is possible to say more about
; this function. The rest of this comment makes those assumptions.
; Ans is a bag with the property that no element of ans mates with any
; other element of ans or with any element of the unprocessed bag. N
; is the next available unique identifier integer; it is always larger
; than any such integer in pairs or in del.
; Abstractly, this function closes B under fn, where B is the bag
; union of the unprocessed bag and ans.
(cond
((null pairs) ans)
((member (caar pairs) del)
(m&m1 (cdr pairs) del ans n fn))
(t (mv-let (mrg y-id)
(m&m-search (cdar pairs) (cdr pairs) del fn)
(cond
((null mrg)
(m&m1 (cdr pairs)
del
(cons (cdar pairs) ans)
n fn))
(t (m&m1 (cons (cons n mrg) (cdr pairs))
(cons y-id del)
ans
(1+ n)
fn)))))))
(defun m&m (bag fn)
; This function takes a bag and a symbol naming a dyadic function, fn,
; known to m&m-apply and about which we assume certain properties
; described below. Let z be (m&m-apply fn x y). Then we say x and y
; "mate" if z is non-nil. If x and y mate, we say z is the "merge" of
; x and y. The name of this function abbreviates the phrase "mate and
; merge".
; We consider each element, x, of bag in turn and seek the first
; successive element, y, that mates with it. If we find one, we throw
; out both, add their merge in place of x and iterate. If we find no
; mate for x, we deposit it in our answer accumulator.
; The specification above is explicit about the order in which we try
; the elements of the bag. If we try to loosen the specification so
; that order is unimportant, we must require that fn have certain
; properties. We discuss this below.
; First, note that we have implicitly assumed that mate and merge are
; commutative because we haven't said in which order we present the
; arguments.
; Second, note that if x doesn't mate with any y, we set it aside in
; our accumulating answer. We do not even try to mate such an x with
; the offspring of the y's it didn't like. This makes us order
; dependent. For example, consider the bag {x y1 y2}. Suppose x
; won't mate with either y1 or y2, but that y1 mates with y2 to
; produce y3 and x mates with y3 to produce y4. Then if we seek mates
; for x first we find none and it gets into our final answer. Then y1
; and y2 mate to form y3. The final answer is hence {x y3}. But if
; we seek mates for y1 first we find y2, produce y3, add it to the
; bag, forming {y3 x}, and then mate x with y3 to get the final answer
; {y4}. This order dependency cannot arise if fn has the property
; that if x mates with the merge of y and z then x mates with either y
; or z. This is called the "distributive" property of mate over merge.
; Third, note that if x does mate with y to produce z then we throw x
; out in favor of z. Thus, x is not mated against any but the first
; y. Thus, if we have {x y1 y2} and x mates with y1 to form z1 and x
; mates with y2 to form z2 and there are no other mates, then we can
; either get {z1 y2} or {z2 y1} as the final bag, depending on whether
; we mate x with y1 or y2. This order dependency cannot arise if fn
; has the property that if x mates with y1 and x mates with y2, then
; (a) the merge of x and y1 mates with y2, and (b) merge has the
; "commutativity-2" (merge (merge x y1) y2) = (merge (merge x y2) y1).
; We call property (a) "non-preclusion" property of mate and merge,
; i.e., merging doesn't preclude mating.
; The commutativity-2 property is implied by associativity and (the
; already assumed commutativity). Thus, another way to avoid the
; third order dependency is if legal merges are associative and have
; the non-preclusion property.
; Important Note: The commonly used fn of unioning together two alists
; that agree on the intersection of their domains, does not have the
; non-preclusion property! Suppose x, y1, and y2 are all alists and
; all map A to 0. Suppose in addition y1 maps B to 1 but y2 maps B to
; 2. Finally, suppose x maps C to 3. Then x mates with both y1 and
; y2. But merging y1 into x precludes mating with y2 and vice versa.
; We claim, but do not prove, that if the mate and merge functions for
; fn are commutative and associative, and have the distributive and
; non-preclusion properties, then m&m is order independent.
; For efficiency we have chosen to implement deletion by keeping a
; list of the deleted elements. But we cannot make a list of the
; deleted elements themselves because there may be duplicate elements
; in the bag and we need to be able to delete occurrences. Thus, the
; workhorse function actually operates on a list of pairs, (i . ele),
; where i is a unique identification integer and ele is an element of
; the bag. In fact we just assign the position of each occurrence to
; each element of the initial bag and thereafter count up as we
; generate new elements.
;
; See m&m1 for the details.
(m&m1 (count-off 0 bag) nil nil (length bag) fn))
; We now develop a much more powerful concept, that of mapping m&m over the
; powerset of a set. This is how we actually merge induction candidates.
; That is, we try to mash together every possible subset of the candidates,
; largest subsets first. See m&m-over-powerset for some implementation
; commentary before going on.
(defun cons-subset-tree (x y)
; We are representing full binary trees of t's and nil's and
; collapsing trees of all nil's to nil and trees of all t's to t. See
; the long comment in m&m-over-powerset. We avoid consing when
; convenient.
(if (eq x t)
(if (eq y t)
t
(if y (cons x y) '(t)))
(if x
(cons x y)
(if (eq y t)
'(nil . t)
(if y (cons x y) nil)))))
(defabbrev car-subset-tree (x)
; See cons-subset-tree.
(if (eq x t) t (car x)))
(defabbrev cdr-subset-tree (x)
; See cons-subset-tree.
(if (eq x t) t (cdr x)))
(defun or-subset-trees (tree1 tree2)
; We disjoin the tips of two binary t/nil trees. See cons-subset-tree.
(cond ((or (eq tree1 t)(eq tree2 t)) t)
((null tree1) tree2)
((null tree2) tree1)
(t (cons-subset-tree (or-subset-trees (car-subset-tree tree1)
(car-subset-tree tree2))
(or-subset-trees (cdr-subset-tree tree1)
(cdr-subset-tree tree2))))))
(defun m&m-over-powerset1 (st subset stree ans fn)
; See m&m-over-powerset.
(cond
((eq stree t) (mv t ans))
((null st)
(let ((z (m&m subset fn)))
(cond ((and z (null (cdr z)))
(mv t (cons (car z) ans)))
(t (mv nil ans)))))
(t
(mv-let (stree1 ans1)
(m&m-over-powerset1 (cdr st)
(cons (car st) subset)
(cdr-subset-tree stree)
ans fn)
(mv-let (stree2 ans2)
(m&m-over-powerset1 (cdr st)
subset
(or-subset-trees
(car-subset-tree stree)
stree1)
ans1 fn)
(mv (cons-subset-tree stree2 stree1) ans2))))))
(defun m&m-over-powerset (st fn)
; Fn is a function known to m&m-apply. Let (fn* s) be defined to be z,
; if (m&m s fn) = {z} and nil otherwise. Informally, (fn* s) is the
; result of somehow mating and merging all the elements of s into a single
; object, or nil if you can't.
; This function applies fn* to the powerset of st and collects all those
; non-nil values produced from maximal s's. I.e., we keep (fn* s) iff it
; is non-nil and no superset of s produces a non-nil value.
; We do this amazing feat (recall that the powerset of a set of n
; things contains 2**n subsets) by generating the powerset in order
; from largest to smallest subsets and don't generate or test any
; subset under a non-nil fn*. Nevertheless, if the size of set is
; very big, this function will get you.
; An informal specification of this function is that it is like m&m
; except that we permit an element to be merged into more than one
; other element (but an element can be used at most once per final
; element) and we try to maximize the amount of merging we can do.
; For example, if x mates with y1 to form z1, and x mates with y2 to
; form z2, and no other mates occur, then this function would
; transform {x y1 y2} into {z1 z2}. It searches by generate and test:
; s (fn* s)
; (x y1 y2) nil
; (x y1) z1
; (x y2) z2
; (x) subsumed
; (y1 y2) nil
; (y1) subsumed
; (y2) subsumed
; nil subsumed
; Here, s1 is "subsumed" by s2 means s1 is a subset of s2. (Just the
; opposite technical definition but exactly the same meaning as in the
; clausal sense.)
; The way we generate the powerset elements is suggested by the
; following trivial von Neumann function, ps, which, when called as in
; (ps set nil), calls PROCESS on each member of the powerset of set,
; in the order in which we generate them:
; (defun ps (set subset)
; (cond ((null set) (PROCESS subset))
; (t (ps (cdr set) (cons (car set) subset)) ;rhs
; (ps (cdr set) subset)))) ;lhs
; By generating larger subsets first we know that if a subset subsumes
; the set we are considering then that subset has already been
; considered. Therefore, we need a way to keep track of the subsets
; with non-nil values. We do this with a "subset tree". Let U be the
; universe of objects in some order. Then the full binary tree with
; depth |U| can be thought of as the powerset of U. In particular,
; any branch through the tree, from top-most node to tip, represents a
; subset of U by labeling the nodes at successive depth by the
; successive elements of U (the topmost node being labeled with the
; first element of U) and adopting the convention that taking a
; right-hand (cdr) branch at a node indicates that the label is in the
; subset and a left-hand (car) branch indicates that the label is not
; in the subset. At the tip of the tree we store a T indicating that
; the subset had a non-nil value or a NIL indicating that it had a nil
; value.
; For storage efficiency we let nil represent an arbitrarily deep full
; binary tree will nil at every tip and we let t represent the
; analogous trees with t at every tip. Car-subset-tree,
; cdr-subset-tree and cons-subset-tree implement these abstractions.
; Of course, we don't have the tree when we start and we generate it
; as we go. That is a really weird idea because generating the tree
; that tells us who was a subset of whom in the past seems to have little
; use as we move forward. But that is not true.
; Observe that there is a correspondence between these trees and the
; function ps above for generating the power set. The recursion
; labeled "rhs" above is going down the right-hand side of the tree
; and the "lhs" recursion is going down the left-hand side. Note that
; we go down the rhs first.
; The neat fact about these trees is that there is a close
; relationship between the right-hand subtree (rhs) and left-hand
; subtree (lhs) of any given node of the tree: lhs can be obtained
; from rhs by turning some nils into ts. The reason is that the tips
; of the lhs of a node labeled by x denote exactly the same subsets
; as the corresponding tips of the right-hand side, except that on the
; right x was present in the subset and on the left it is not. So
; when we do the right hand side we come back with a tree and if we
; used that very tree for the left hand side (interpreting nil as
; meaning "compute it and see" and t as meaning "a superset of this
; set has non-nil value") then it is correct. But we can do a little
; better than that because we might have come into this node with a
; tree (i.e., one to go into the right hand side with and another to go
; into the left hand side with) and so after we have gone into the
; right and come back with its new tree, we can disjoin the output of
; the right side with the input for the left side to form the tree we
; will actually use to explore the left side.
(mv-let (stree ans)
(m&m-over-powerset1 st nil nil nil fn)
(declare (ignore stree))
ans))
; Ok, so now we have finished the selection process and we begin the
; construction of the induction formula itself.
(defun all-picks2 (pocket pick ans)
; See all-picks.
(cond ((null pocket) ans)
(t (cons (cons (car pocket) pick)
(all-picks2 (cdr pocket) pick ans)))))
(defun all-picks2r (pocket pick ans)
; See all-picks.
(cond ((null pocket) ans)
(t (all-picks2r (cdr pocket) pick
(cons (cons (car pocket) pick) ans)))))
(defun all-picks1 (pocket picks ans rflg)
; See all-picks.
(cond ((null picks) ans)
(t (all-picks1 pocket (cdr picks)
(if rflg
(all-picks2r pocket (car picks) ans)
(all-picks2 pocket (car picks) ans))
rflg))))
(defun all-picks (pockets rflg)
; Pockets is a list of pockets, each pocket containing 0 or more
; objects. We return a list of all the possible ways you can pick one
; thing from each pocket. If rflg is nil initially, then the order of
; the resulting list is exactly the same as it was in nqthm. There is
; not much else to recommend this particular choice of definition!
; Historical Plaque from Nqthm:
; (DEFUN ALL-PICKS (POCKET-LIST)
; (COND ((NULL POCKET-LIST) (LIST NIL))
; (T (ITERATE FOR PICK IN (ALL-PICKS (CDR POCKET-LIST))
; NCONC (ITERATE FOR CHOICE IN (CAR POCKET-LIST)
; COLLECT (CONS CHOICE PICK))))))
; Nqthm's construction is a very natural recursive one, except that it
; used nconc to join together the various segments of the answer. If
; we tried the analogous construction here we would have to append the
; segments together and copy a very long list. So we do it via an
; accumulator. The trouble however is that we reverse the order of
; the little buckets in our answer every time we process a pocket. We
; could avoid that if we wanted to recurse down the length of our
; answer on recursive calls, but we were afraid of running out of
; stack, and so we have coded this with tail recursion only. We do
; non-tail recursion only over short things like individual pockets or
; the list of pockets. And so to (a) avoid unnecessary copying, (b)
; non-tail recursion, and (c) constructing our answer in a different
; order, we introduced rflg. Rflg causes us either to reverse or not
; reverse a certain intermediate result every other recursion. It
; would be reassuring to see a mechanically checked proof that this
; definition of all-picks is equivalent to nqthm's.
(cond ((null pockets) '(nil))
(t (all-picks1 (car pockets)
(all-picks (cdr pockets) (not rflg))
nil
rflg))))
(defun dumb-negate-lit-lst-lst (cl-set)
; We apply dumb-negate-lit-lst to every list in cl-set and collect the
; result. You can think of this as negating a clause set (i.e., an
; implicit conjunction of disjunctions), but you have to then imagine
; that the implicit "and" at the top has been turned into an "or" and
; vice versa at the lower level.
(cond ((null cl-set) nil)
(t (cons (dumb-negate-lit-lst (car cl-set))
(dumb-negate-lit-lst-lst (cdr cl-set))))))
(defun induction-hyp-clause-segments2 (alists cl ans)
; See induction-hyp-clause-segments1.
(cond ((null alists) ans)
(t (cons (sublis-var-lst (car alists) cl)
(induction-hyp-clause-segments2 (cdr alists) cl ans)))))
(defun induction-hyp-clause-segments1 (alists cl-set ans)
; This function applies all of the substitutions in alists to all of
; the clauses in cl-set and appends the result to ans to create one
; list of instantiated clauses.
(cond ((null cl-set) ans)
(t (induction-hyp-clause-segments2
alists
(car cl-set)
(induction-hyp-clause-segments1 alists (cdr cl-set) ans)))))
(defun induction-hyp-clause-segments (alists cl-set)
; Cl-set is a set of clauses. We are trying to prove the conjunction
; over that set, i.e., cl1 & cl2 ... & clk, by induction. We are in a
; case in which we can assume every instance under alists of that
; conjunction. Thus, we can assume any lit from cl1, any lit from
; cl2, etc., instantiated via all of the alists. We wish to return a
; list of clause segments. Each segment will be spliced into the a
; clause we are trying to prove and together the resulting set of
; clauses is supposed to be equivalent to assuming all instances of
; the conjunction over cl-set.
; So one way to create the answer would be to first instantiate each
; of the k clauses with each of the n alists, getting a set of n*k
; clauses. Then we could run all-picks over that, selecting one
; literal from each of the instantiated clauses to assume. Then we'd
; negate each literal within each pick to create a clause hypothesis
; segment. That is nearly what we do, except that we do the negation
; first so as to share structure among the all-picks answers.
; Note: The code below calls (dumb-negate-lit lit) on each lit. Nqthm
; used (negate-lit lit nil ...) on each lit, employing
; negate-lit-lst-lst, which has since been deleted but was strictly
; analogous to the dumb version called below. But since the
; type-alist is nil in Nqthm's call, it seems unlikely that the
; literal will be decided by type-set. We changed to dumb-negate-lit
; to avoid having to deal both with ttrees and the enabled structure
; implicit in type-set.
(all-picks
(induction-hyp-clause-segments1 alists
(dumb-negate-lit-lst-lst cl-set)
nil)
nil))
(defun induction-formula3 (neg-tests hyp-segments cl ans)
; Neg-tests is the list of the negated tests of an induction
; tests-and-alists entry. hyp-segments is a list of hypothesis clause
; segments (i.e., more negated tests), and cl is a clause. For each
; hyp segment we create the clause obtained by disjoining the tests,
; the segment, and cl. We conjoin the resulting clauses to ans.
; See induction-formula for a comment about this iteration.
(cond
((null hyp-segments) ans)
(t (induction-formula3 neg-tests
(cdr hyp-segments)
cl
(conjoin-clause-to-clause-set
; Historical Plaque from Nqthm:
; We once implemented the idea of "homographication" in which we combined
; both induction, opening up of the recursive fns in the conclusion, and
; generalizing away some recursive calls. This function did the expansion
; and generalization. If the idea is reconsidered the following theorems are
; worthy of consideration:
; (ORDERED (SORT X)),
; (IMPLIES (ORDERED X)
; (ORDERED (ADDTOLIST I X))),
; (IMPLIES (AND (NUMBER-LISTP X)
; (ORDERED X)
; (NUMBERP I)
; (NOT (< (CAR X) I)))
; (EQUAL (ADDTOLIST I X) (CONS I X))), and
; (IMPLIES (AND (NUMBER-LISTP X) (ORDERED X)) (EQUAL (SORT X) X)).
; Observe that we simply disjoin the negated tests, hyp segments, and clause.
; Homographication further manipulated the clause before adding it to the
; answer.
(disjoin-clauses
neg-tests
(disjoin-clauses (car hyp-segments) cl))
ans)))))
(defun induction-formula2 (cl cl-set ta-lst ans)
; Cl is a clause in cl-set, which is a set of clauses we are proving
; by induction. Ta-lst is the tests-and-alists-lst component of the
; induction candidate we are applying to prove cl-set. We are now
; focused on the proof of cl, using the induction schema of ta-lst
; but getting to assume all the clauses in cl-set in our induction
; hypothesis. We will map across ta-lst, getting a set of tests and
; some alists at each stop, and for each stop add a bunch of clauses
; to ans.
(cond
((null ta-lst) ans)
(t (induction-formula2 cl cl-set (cdr ta-lst)
(induction-formula3
; Note: Nqthm used (negate-lit-lst ... nil ...), but since the
; type-alist supplied was nil, we decided it was probably no buying us
; much -- not as much as passing up the ttrees would cost in terms of
; coding work!
(dumb-negate-lit-lst
(access tests-and-alists (car ta-lst) :tests))
(induction-hyp-clause-segments
(access tests-and-alists (car ta-lst) :alists)
cl-set)
cl
ans)))))
(defun induction-formula1 (lst cl-set ta-lst ans)
; Lst is a tail of cl-set. Cl-set is a set of clauses we are trying to prove.
; Ta-lst is the tests-and-alists-lst component of the induction candidate
; we wish to apply to cl-set. We map down lst forming a set of clauses
; for each cl in lst. Basically, the set we form for cl is of the form
; ... -> cl, where ... involves all the case analysis under the tests in
; ta-lst and all the induction hypotheses from cl-set under the alists in
; each test-and-alists. We add our clauses to ans.
(cond
((null lst) ans)
(t (induction-formula1 (cdr lst) cl-set ta-lst
(induction-formula2 (car lst)
cl-set ta-lst ans)))))
(defun induction-formula (cl-set ta-lst)
; Cl-set is a set of clauses we are to try to prove by induction, applying
; the inductive scheme described by the tests-and-alists-lst, ta-lst,
; of some induction candidate. The following historical plaque tells all.
; Historical Plaque from Nqthm:
; TESTS-AND-ALISTS-LST is a such a list that the disjunction of the
; conjunctions of the TESTS components of the members is T. Furthermore,
; there exists a measure M, a well-founded relation R, and a sequence of
; variables x1, ..., xn such that for each T&Ai in TESTS-AND-ALISTS-LST, for
; each alist alst in the ALISTS component of T&Ai, the conjunction of the
; TESTS component, say qi, implies that (R (M x1 ... xn)/alst (M x1 ... xn)).
; To prove thm, the conjunction of the disjunctions of the members of CL-SET,
; it is sufficient, by the principle of induction, to prove instead the
; conjunction of the terms qi & thm' & thm'' ... -> thm, where the primed
; terms are the results of substituting the alists in the ALISTS field of the
; ith member of TESTS-AND-ALISTS-LST into thm.
; If thm1, thm2, ..., thmn are the disjunctions of the members of CL-SET,
; then it is sufficient to prove all of the formulas qi & thm' & thm'' ...
; -> thmj. This is a trivial proposition fact, to prove (IMPLIES A (AND B
; C)) it is sufficient to prove (IMPLIES A B) and (IMPLIES A C).
; The (ITERATE FOR PICK ...)* expression below returns a list of
; clauses whose conjunction propositionally implies qi & thm' &
; thm'' ... -> thmj, where TA is the ith member of
; TESTS-AND-ALISTS-LST and CL is the jth member of CL-SET. Proof:
; Let THM have the form:
;
; (AND (OR a1 ...)
; (OR b1 ...)
; ...
; (OR z1 ...)).
; Then qi & thm' & thm'' ... -> thmj has the form:
; (IMPLIES (AND qi
; (AND (OR a1 ... )
; (OR b1 ... )
; ...
; (OR z1 ... ))'
; (AND (OR a1 ... )
; (OR b1 ... )
; ...
; (OR z1 ... ))''
; ...
; (AND (OR a1 ... )
; (OR b1 ... )
; ...
; (OR z1 ... )))'''...'
; thmj).
;
; Suppose this formula is false for some values of the free variables. Then
; under those values, each disjunction in the hypothesis is true. Thus there
; exists a way of choosing one literal from each of the disjunctions, all of
; which are true. This choice is one of the PICKs below. But we prove that
; (IMPLIES (AND qi PICK) thmj).
; Note: The (ITERATE FOR PICK ...) expression mentioned above is the function
; induction-formula3 above.
(m&m (reverse (induction-formula1 cl-set cl-set ta-lst nil))
'subsetp-equal/smaller))
; Because the preceding computation is potentially explosive we will
; sometimes reduce its complexity by shrinking the given clause set to
; a singleton set containing a unit clause. To decide whether to do that
; we will use the following rough measures:
(defun all-picks-size (cl-set)
; This returns the size of the all-picks computed by induction-formula3.
(cond ((null cl-set) 1)
(t (* (length (car cl-set)) (all-picks-size (cdr cl-set))))))
(defun induction-formula-size1 (hyps-size concl-size ta-lst)
; We determine roughly the number of clauses that ta-lst will generate when
; the number of all-picks through the hypotheses is hyps-size and the
; number of conclusion clauses is concl-size. The individual cases of
; the tests-and-alists combine additively. But we must pick our way through
; the hyps for each instantiation.
(cond ((null ta-lst) 0)
(t
(+ (* concl-size (expt hyps-size
(length (access tests-and-alists
(car ta-lst)
:alists))))
(induction-formula-size1 hyps-size concl-size (cdr ta-lst))))))
(defun induction-formula-size (cl-set ta-lst)
; This function returns a rough upper bound on the number of clauses
; that will be generated by induction-formula on the given arguments.
; See the comment in that function.
(induction-formula-size1 (all-picks-size cl-set)
(length cl-set)
ta-lst))
; The following constant determines the limit on the estimated number of
; clauses induct, below, will return. When normal processing would exceed
; this number, we try to cut down the combinatorics by collapsing clauses
; back into terms.
(defconst *maximum-induct-size* 100)
; And here is how we convert a hairy set of clauses into a term when we
; have to.
(defun termify-clause-set (clauses)
; This function is similar to termify-clause except that it converts a
; set of clauses into an equivalent term. The set of clauses is
; understood to be implicitly conjoined and we therefore produce a
; conjunction expressed as (if cl1 cl2 nil).
(declare (xargs :guard (pseudo-term-list-listp clauses)))
(cond ((null clauses) *t*)
((null (cdr clauses)) (disjoin (car clauses)))
(t (mcons-term* 'if
(disjoin (car clauses))
(termify-clause-set (cdr clauses))
*nil*))))
; Once we have created the set of clauses to prove, we inform the
; simplifier of what to look out for during the early processing.
(defun inform-simplify3 (alist terms ans)
; Instantiate every term in terms with alist and add them to ans.
(cond ((null terms) ans)
(t (inform-simplify3 alist (cdr terms)
(add-to-set-equal (sublis-var alist (car terms))
ans)))))
(defun inform-simplify2 (alists terms ans)
; Using every alist in alists, instantiate every term in terms and add
; them all to ans.
(cond ((null alists) ans)
(t (inform-simplify2 (cdr alists) terms
(inform-simplify3 (car alists) terms ans)))))
(defun inform-simplify1 (ta-lst terms ans)
; Using every alist mentioned in any tests-and-alists record of ta-lst
; we instantiate every term in terms and add them all to ans.
(cond ((null ta-lst) ans)
(t (inform-simplify1 (cdr ta-lst) terms
(inform-simplify2 (access tests-and-alists
(car ta-lst)
:alists)
terms
ans)))))
(defun inform-simplify (ta-lst terms pspv)
; Historical Plaque from Nqthm:
; Two of the variables effecting REWRITE are TERMS-TO-BE-IGNORED-BY-REWRITE
; and EXPAND-LST. When any term on the former is encountered REWRITE returns
; it without rewriting it. Terms on the latter must be calls of defined fns
; and when encountered are replaced by the rewritten body.
; We believe that the theorem prover will perform significantly faster on
; many theorems if, after an induction, it does not waste time (a) trying to
; simplify the recursive calls introduced in the induction hypotheses and (b)
; trying to decide whether to expand the terms inducted for in the induction
; conclusion. This suspicion is due to some testing done with the idea of
; "homographication" which was just a jokingly suggested name for the idea of
; generalizing the recursive calls away at INDUCT time after expanding the
; induction terms in the conclusion. Homographication speeded the
; theorem-prover on many theorems but lost on several others because of the
; premature generalization. See the comment in FORM-INDUCTION-CLAUSE.
; To avoid the generalization at INDUCT time we are going to try using
; TERMS-TO-BE-IGNORED-BY-REWRITE. The idea is this, during the initial
; simplification of a clause produced by INDUCT we will have the recursive
; terms on TERMS-TO-BE-IGNORED-BY-REWRITE. When the clause settles down --
; hopefully it will often be proved first -- we will restore
; TERMS-TO-BE-IGNORED-BY-REWRITE to its pre-INDUCT value. Note however that
; we have to mess with TERMS-TO-BE-IGNORED-BY-REWRITE on a clause by clause
; basis, not just once in INDUCT.
; So here is the plan. INDUCT will set INDUCTION-HYP-TERMS to the list of
; instances of the induction terms, and will set INDUCTION-CONCL-TERMS to the
; induction terms themselves. SIMPLIFY-CLAUSE will look at the history of
; the clause to determine whether it has settled down since induction. If
; not it will bind TERMS-TO-BE-IGNORED-BY-REWRITE to the concatenation of
; INDUCTION-HYP-TERMS and its old value and will analogously bind EXPAND-LST.
; A new process, called SETTLED-DOWN-SENT, will be used to mark when in the
; history the clause settled down.
; In a departure from Nqthm, starting with Version_2.8, we do not wait for
; settled-down before turning off the above special consideration given to
; induction-hyp-terms and induction-concl-terms. See simplify-clause for
; details.
(change prove-spec-var pspv
:induction-concl-terms terms
:induction-hyp-terms (inform-simplify1 ta-lst terms nil)))
; Ok, except for our output and putting it all together, that's induction.
; We now turn to the output. Induct prints two different messages. One
; reports the successful choice of an induction. The other reports failure.
(defun all-vars1-lst-lst (lst ans)
; Lst is a list of lists of terms. For example, it might be a set of
; clauses. We compute the set of all variables occurring in it.
(cond ((null lst) ans)
(t (all-vars1-lst-lst (cdr lst)
(all-vars1-lst (car lst) ans)))))
(defun gen-new-name1 (char-lst wrld i)
(let ((name (intern
(coerce
(append char-lst
(explode-nonnegative-integer i 10 nil))
'string)
"ACL2")))
(cond ((new-namep name wrld) name)
(t (gen-new-name1 char-lst wrld (1+ i))))))
(defun gen-new-name (root wrld)
; Create from the symbol root a possibly different symbol that
; is a new-namep in wrld.
(cond ((new-namep root wrld) root)
(t (gen-new-name1 (coerce (symbol-name root) 'list) wrld 0))))
(defun unmeasured-variables3 (vars alist)
; See unmeasured-variables.
(cond ((null alist) nil)
((or (member-eq (caar alist) vars)
(eq (caar alist) (cdar alist)))
(unmeasured-variables3 vars (cdr alist)))
(t (cons (caar alist) (unmeasured-variables3 vars (cdr alist))))))
(defun unmeasured-variables2 (vars alists)
; See unmeasured-variables.
(cond ((null alists) nil)
(t (union-eq (unmeasured-variables3 vars (car alists))
(unmeasured-variables2 vars (cdr alists))))))
(defun unmeasured-variables1 (vars ta-lst)
; See unmeasured-variables.
(cond ((null ta-lst) nil)
(t (union-eq (unmeasured-variables2 vars
(access tests-and-alists
(car ta-lst)
:alists))
(unmeasured-variables1 vars (cdr ta-lst))))))
(defun unmeasured-variables (measured-vars cand)
; Measured-vars is the :subset of measured variables from the measure of term,
; computed above, for cand. We collect those variables that are changed by
; some substitution but are not measured by our induction measure. These are
; simply brought to the user's attention because we find it often surprising to
; see them.
(unmeasured-variables1 measured-vars
(access candidate cand :tests-and-alists-lst)))
(defun tilde-@-well-founded-relation-phrase (rel wrld)
; We return a ~@ message that prints as "the relation rel (which, by name, is
; known to be well-founded on the domain recognized by mp)" and variants of
; that obtained when name is nil (meaning the well-foundedness is built in)
; and/or mp is t (meaning the domain is the universe).
(let* ((temp (assoc-eq rel (global-val 'well-founded-relation-alist wrld)))
(mp (cadr temp))
(base-symbol (base-symbol (cddr temp))))
(msg "the relation ~x0 (which~#1~[ ~/, by ~x2, ~]is known to be ~
well-founded~#3~[~/ on the domain recognized by ~x4~])"
rel
(if (null base-symbol) 0 1)
base-symbol
(if (eq mp t) 0 1)
mp)))
(defun measured-variables (cand wrld)
(all-vars1-lst
(subcor-var-lst (formals (ffn-symb (access candidate cand :induction-term))
wrld)
(fargs (access candidate cand :induction-term))
(access justification
(access candidate cand :justification)
:subset))
nil))
(defun induct-msg/continue (pool-lst
forcing-round
cl-set
induct-hint-val
len-candidates
len-flushed-candidates
len-merged-candidates
len-unvetoed-candidates
len-complicated-candidates
len-high-scoring-candidates
winning-candidate
estimated-size
clauses
wrld
state)
; Pool-lst is what is passed to form the tilde-@-pool-name-phrase (q.v.) of the
; set of clauses cl-set to which we are applying induction. Len-candidates is
; the length of the list of induction candidates we found.
; Len-flushed-candidates is the length of the candidates after flushing some
; down others, etc. Winning-candidate is the final selection. Clauses is the
; clause set generated by applying winning-candidate to cl-set. Wrld and state
; are the usual.
; This function increments timers. Upon entry, the accumulated time is
; charged to 'prove-time. The time spent in this function is charged
; to 'print-time.
; Warning: This function should be called under (io? prove ...).
(declare (xargs
; Avoid blow-up from (skip-proofs (verify-termination ...)), which otherwise
; takes a long time (e.g., when executed on behalf of community books utility
; verify-guards-program).
:normalize nil))
(cond
((and (gag-mode)
(or (eq (gag-mode-evisc-tuple state) t)
(cdr pool-lst)))
state)
(t
(pprogn
(increment-timer 'prove-time state)
(let* ((pool-name
(tilde-@-pool-name-phrase forcing-round pool-lst))
(p (cons :p
(merge-sort-term-order (all-vars1-lst-lst cl-set nil))))
(measured-variables (measured-variables winning-candidate wrld))
(unmeasured-variables (unmeasured-variables measured-variables
winning-candidate))
(attribution-phrase (tilde-*-simp-phrase
(access candidate winning-candidate :ttree))))
(fms "~#H~[We have been told to use induction. ~N0 induction ~
scheme~#1~[ is~/s are~] suggested by the induction ~
hint.~/~
We have been told to use induction. ~N0 induction ~
scheme~#1~[ is~/s are~] suggested by this ~
conjecture.~/~
Perhaps we can prove ~@n by induction. ~
~N0 induction scheme~#1~[ is~/s are~] suggested by this ~
conjecture.~] ~
~#a~[~/Subsumption reduces that number to ~n2. ~]~
~#b~[~/These merge into ~n3 derived induction scheme~#4~[~/s~]. ~]~
~#c~[~/However, ~n5 of these ~#6~[is~/are~] flawed and so we are ~
left with ~nq viable ~#r~[~/candidate~/candidates~]. ~]~
~#d~[~/By considering those suggested by the largest number of ~
non-primitive recursive functions, we narrow the field ~
to ~n7. ~]~
~#e~[~/~N8 of these ~
~#9~[has a score higher than the other~#A~[~/s~]. ~/~
are tied for the highest score. ~]~]~
~#f~[~/We will choose arbitrarily among these. ~]~
~|~%We will induct according to a scheme suggested by ~
~#h~[~pg.~/~pg, but modified to accommodate ~*i.~]~
~#w~[~/ ~#h~[This suggestion was~/These suggestions were~] ~
produced using ~*x.~] ~
If we let ~pp denote ~@n above then the induction scheme ~
we'll use is~|~
~Qsy.~
This induction is justified by the same argument used ~
to admit ~xj. ~
~#l~[~/Note, however, that the unmeasured ~
variable~#m~[ ~&m is~/s ~&m are~] being instantiated. ~]~
When applied to the goal at hand the above induction scheme ~
produces ~#v~[no nontautological subgoals~/one nontautological ~
subgoal~/~no nontautological subgoals~].~
~#t~[~/ However, to achieve this relatively small number of ~
cases we had to fold ~@n into a single IF-expression. Had we ~
left it as a set of clauses this induction would have produced ~
approximately ~nu cases! Chances are that this proof attempt ~
is about to blow up in your face (and all over our memory ~
boards).~]~|"
(list (cons #\H (cond ((null induct-hint-val) 2)
((equal induct-hint-val *t*) 1)
(t 0)))
(cons #\n pool-name)
(cons #\0 len-candidates)
(cons #\1 (if (int= len-candidates 1) 0 1))
(cons #\a (if (< len-flushed-candidates
len-candidates)
1 0))
(cons #\2 len-flushed-candidates)
(cons #\b (if (< len-merged-candidates
len-flushed-candidates)
1 0))
(cons #\3 len-merged-candidates)
(cons #\4 (if (int= len-merged-candidates 1) 0 1))
(cons #\c (if (< len-unvetoed-candidates
len-merged-candidates)
1 0))
(cons #\5 (- len-merged-candidates
len-unvetoed-candidates))
(cons #\q len-unvetoed-candidates)
(cons #\y (gag-mode-evisc-tuple state)) ; is not t
(cons #\r (zero-one-or-more len-unvetoed-candidates))
(cons #\6 (if (int= (- len-merged-candidates
len-unvetoed-candidates)
1)
0 1))
(cons #\d (if (< len-complicated-candidates
len-unvetoed-candidates)
1 0))
(cons #\7 len-complicated-candidates)
(cons #\e (if (< len-high-scoring-candidates
len-complicated-candidates)
1 0))
(cons #\8 len-high-scoring-candidates)
(cons #\9 (if (int= len-high-scoring-candidates 1) 0 1))
(cons #\A (if (int= (- len-complicated-candidates
len-high-scoring-candidates)
1)
0 1))
(cons #\f (if (int= len-high-scoring-candidates 1) 0 1))
(cons #\p p)
(cons #\s (prettyify-clause-set
(induction-formula
(list (list p))
(access candidate
winning-candidate
:tests-and-alists-lst))
(let*-abstractionp state)
wrld))
(cons #\g (untranslate (access candidate winning-candidate
:xinduction-term)
nil
wrld))
(cons #\h (if (access candidate winning-candidate :xancestry)
1 0))
(cons #\i (tilde-*-untranslate-lst-phrase
(access candidate winning-candidate :xancestry)
nil wrld))
(cons #\j (ffn-symb
(access candidate winning-candidate
:xinduction-term)))
(cons #\l (if unmeasured-variables 1 0))
(cons #\m unmeasured-variables)
(cons #\o (length clauses))
(cons #\t (if (> estimated-size *maximum-induct-size*)
1
0))
(cons #\u estimated-size)
(cons #\v (if (null clauses) 0 (if (cdr clauses) 2 1)))
(cons #\w (if (nth 4 attribution-phrase) 1 0))
(cons #\x attribution-phrase))
(proofs-co state)
state
(term-evisc-tuple nil state)))
(increment-timer 'print-time state)))))
(mutual-recursion
(defun rec-fnnames (term wrld)
(cond ((variablep term) nil)
((fquotep term) nil)
((flambda-applicationp term)
(union-eq (rec-fnnames (lambda-body (ffn-symb term)) wrld)
(rec-fnnames-lst (fargs term) wrld)))
((getpropc (ffn-symb term) 'recursivep nil wrld)
(add-to-set-eq (ffn-symb term)
(rec-fnnames-lst (fargs term) wrld)))
(t (rec-fnnames-lst (fargs term) wrld))))
(defun rec-fnnames-lst (lst wrld)
(cond ((null lst) nil)
(t (union-eq (rec-fnnames (car lst) wrld)
(rec-fnnames-lst (cdr lst) wrld)))))
)
(defun induct-msg/lose (pool-name induct-hint-val pspv state)
; We print the message that no induction was suggested.
; This function increments timers. Upon entry, the accumulated time is
; charged to 'prove-time. The time spent in this function is charged
; to 'print-time.
; Warning: This function should be called under (io? prove ...).
(pprogn
(increment-timer 'prove-time state)
(fms "No induction schemes are suggested by ~#H~[the induction ~
hint.~@?~/~@n.~] Consequently, the proof attempt has failed.~|"
(list (cons #\H (cond (induct-hint-val 0) (t 1)))
(cons #\n pool-name)
(cons #\?
(and induct-hint-val ; optimization
(let* ((wrld (w state))
(all-fns (all-fnnames induct-hint-val))
(rec-fns (rec-fnnames induct-hint-val wrld)))
(cond
((null all-fns)
" (Note that there is no function symbol ~
occurring in that hint.)")
((and (null rec-fns)
(null (cdr all-fns)))
(msg " (Note that ~x0 is not defined ~
recursively, so it cannot suggest an ~
induction scheme.)"
(car all-fns)))
((null rec-fns)
" (Note that none of its function symbols is ~
defined recursively, so they cannot suggest ~
induction schemes.)")
((and (all-variablep (fargs induct-hint-val))
(let ((ens (ens-from-pspv pspv)))
(and
(not (enabled-runep
(list :induction (car rec-fns))
ens
wrld))
(not (enabled-runep
(list :definition (car rec-fns))
ens
wrld)))))
(msg " (Note that ~x0 (including its :induction ~
rune) is disabled, so it cannot suggest an ~
induction scheme. Consider providing an ~
:in-theory hint that enables ~x0 or ~x1.)"
(car all-fns)
(list :induction (car all-fns))))
(t ""))))))
(proofs-co state)
state
(term-evisc-tuple nil state))
(increment-timer 'print-time state)))
; When induct is called it is supplied the hint-settings that were
; attached to the clause by the user. Induct has the job of loading
; the hint settings into the pspv it returns. Most of the content of
; the hint-settings is loaded into the rewrite-constant of the pspv.
(defun@par load-hint-settings-into-rcnst (hint-settings rcnst
incrmt-array-name-info
wrld ctx state)
; Certain user supplied hint settings find their way into the rewrite-constant.
; They are :expand, :restrict, :hands-off, and :in-theory. Our convention is
; that if a given hint key/val is provided it replaces what was in the rcnst.
; Otherwise, we leave the corresponding field of rcnst unchanged.
; Incrmt-array-name-info is either a clause-id, a keyword, or nil. If it is a
; clause-id and we install a new enabled structure, then we will use that
; clause-id to build the array name, rather than simply incrementing a suffix.
; Otherwise incrmt-array-name-info is a keyword. A keyword value should be
; used for calls made by user applications, for example in community book
; books/tools/easy-simplify.lisp, so that enabled structures maintained by the
; ACL2 system do not lose their associated von Neumann arrays.
(er-let*@par
((new-ens
(cond
((assoc-eq :in-theory hint-settings)
(load-theory-into-enabled-structure@par
:from-hint
(cdr (assoc-eq :in-theory hint-settings))
nil
(access rewrite-constant rcnst :current-enabled-structure)
(or incrmt-array-name-info t)
nil
wrld ctx state))
(t (value@par (access rewrite-constant rcnst
:current-enabled-structure))))))
(value@par (change rewrite-constant rcnst
:rw-cache-state
(cond
((assoc-eq :rw-cache-state hint-settings)
(cdr (assoc-eq :rw-cache-state hint-settings)))
(t (access rewrite-constant rcnst :rw-cache-state)))
:expand-lst
(cond
((assoc-eq :expand hint-settings)
(cdr (assoc-eq :expand hint-settings)))
(t (access rewrite-constant rcnst :expand-lst)))
:restrictions-alist
(cond
((assoc-eq :restrict hint-settings)
(cdr (assoc-eq :restrict hint-settings)))
(t (access rewrite-constant rcnst
:restrictions-alist)))
:fns-to-be-ignored-by-rewrite
(cond
((assoc-eq :hands-off hint-settings)
(cdr (assoc-eq :hands-off hint-settings)))
(t (access rewrite-constant rcnst
:fns-to-be-ignored-by-rewrite)))
:current-enabled-structure
new-ens
:nonlinearp
(cond
((assoc-eq :nonlinearp hint-settings)
(cdr (assoc-eq :nonlinearp hint-settings)))
(t (access rewrite-constant rcnst :nonlinearp)))
:backchain-limit-rw
(cond
((assoc-eq :backchain-limit-rw hint-settings)
(cdr (assoc-eq :backchain-limit-rw hint-settings)))
(t (access rewrite-constant rcnst
:backchain-limit-rw)))
:case-split-limitations
(cond
((assoc-eq :case-split-limitations hint-settings)
(cdr (assoc-eq :case-split-limitations
hint-settings)))
(t (access rewrite-constant rcnst
:case-split-limitations)))))))
(defun update-hint-settings (new-hint-settings old-hint-settings)
(cond
((endp new-hint-settings) old-hint-settings)
((assoc-eq (caar new-hint-settings) old-hint-settings)
(update-hint-settings
(cdr new-hint-settings)
(cons (car new-hint-settings)
(delete-assoc-eq (caar new-hint-settings)
old-hint-settings))))
(t (update-hint-settings
(cdr new-hint-settings)
(cons (car new-hint-settings) old-hint-settings)))))
; Thus, a given hint-settings causes us to modify the pspv as follows:
(defun@par load-hint-settings-into-pspv (increment-flg hint-settings pspv cl-id
wrld ctx state)
; We load the hint-settings into the rewrite-constant of pspv, thereby making
; available the :expand, :case-split-limitations, :restrict, :hands-off,
; :in-theory, and :rw-cache-state hint settings. We also store the
; hint-settings in the hint-settings field of the pspv, making available the
; :induct and :do-not-induct hint settings.
; When increment-flg is non-nil, we want to preserve the input pspv's hint
; settings except when they collide with hint-settings. Otherwise (for
; example, when induct is called), we completely replace the input pspv's
; :hint-settings with hint-settings.
; Warning: Restore-hint-settings-in-pspv, below, is supposed to undo these
; changes while not affecting the rest of a newly obtained pspv. Keep these
; two functions in step.
(er-let*@par
((rcnst (load-hint-settings-into-rcnst@par
hint-settings
(access prove-spec-var pspv :rewrite-constant)
cl-id wrld ctx state)))
(value@par
(change prove-spec-var pspv
:rewrite-constant rcnst
:hint-settings
(if increment-flg
(update-hint-settings hint-settings
(access prove-spec-var pspv
:hint-settings))
hint-settings)))))
(defun restore-hint-settings-in-pspv (new-pspv old-pspv)
; This considers the fields changed by load-hint-settings-into-pspv above
; and restores them in new-pspv to the values they have in old-pspv. The
; idea is that we start with a pspv1, load hints into it to get pspv2,
; pass that around the prover and obtain pspv3 (which has a new tag-tree
; and pool etc), and then restore the hint settings as they were in pspv1.
; In this example, new-pspv would be pspv3 and old-pspv would be pspv1.
; We would like the garbage collector to free up space from obsolete arrays of
; enabled-structures. This may be especially important with potentially many
; such arrays associated with different names, due to the new method of
; creating array names after Version_4.1, where the name is typically based on
; the clause-id. Previously, the enabled-structure array names were created
; based on just a few possible suffixes, so it didn't seem important to make
; garbage -- each time such a name was re-used, the previous array for that
; name became garbage. If we change how this is done, revisit the sentence
; about this function in the Essay on Enabling, Enabled Structures, and
; Theories.
(let* ((old-rcnst (access prove-spec-var old-pspv
:rewrite-constant))
(old-ens (access rewrite-constant old-rcnst
:current-enabled-structure))
(old-name (access enabled-structure old-ens
:array-name))
(new-rcnst (access prove-spec-var new-pspv
:rewrite-constant))
(new-ens (access rewrite-constant new-rcnst
:current-enabled-structure))
(new-name (access enabled-structure new-ens
:array-name)))
(prog2$ (cond ((equal old-name new-name) nil)
(t (flush-compress new-name)))
(change prove-spec-var new-pspv
:rewrite-constant old-rcnst
:hint-settings (access prove-spec-var old-pspv
:hint-settings)))))
(defun remove-trivial-clauses (clauses wrld)
(cond
((null clauses) nil)
((trivial-clause-p (car clauses) wrld)
(remove-trivial-clauses (cdr clauses) wrld))
(t (cons (car clauses)
(remove-trivial-clauses (cdr clauses) wrld)))))
#+:non-standard-analysis
(defun non-standard-vector-check (vars accum)
(if (null vars)
accum
(non-standard-vector-check (cdr vars)
(cons (mcons-term* 'standardp (car vars))
accum))))
#+:non-standard-analysis
(defun merge-ns-check (checks clause accum)
(if (null checks)
accum
(merge-ns-check (cdr checks) clause (cons (cons (car checks)
clause)
accum))))
#+:non-standard-analysis
(defun trap-non-standard-vector-aux (cl-set accum-cl checks wrld)
(cond ((null cl-set) accum-cl)
((classical-fn-list-p (all-fnnames-lst (car cl-set)) wrld)
(trap-non-standard-vector-aux (cdr cl-set) accum-cl checks wrld))
(t
(trap-non-standard-vector-aux (cdr cl-set)
(append (merge-ns-check checks
(car cl-set)
nil)
accum-cl)
checks
wrld))))
#+:non-standard-analysis
(defun remove-adjacent-duplicates (x)
; We have slightly modified the original definition so as to match the
; definition (quite likely adapted from the original one here) in community
; book books/defsort/remove-dups.lisp. Sol Swords points out that an
; unconditional rule true-listp-of-remove-adjacent-duplicates in that book
; relies on (list (car x)) in the second case below, rather than x.
(declare (xargs :guard t))
(cond ((atom x)
nil)
((atom (cdr x))
(list (car x))) ; See comment above for why this is not x.
((equal (car x) (cadr x))
(remove-adjacent-duplicates (cdr x)))
(t
(cons (car x)
(remove-adjacent-duplicates (cdr x))))))
(defun remove-adjacent-duplicates-eq (x)
; See remove-adjacent-duplicates.
(declare (xargs :guard t))
(cond ((atom x)
nil)
((atom (cdr x))
(list (car x)))
((eq (car x) (cadr x))
(remove-adjacent-duplicates-eq (cdr x)))
(t
(cons (car x)
(remove-adjacent-duplicates-eq (cdr x))))))
#+:non-standard-analysis
(defun non-standard-induction-vars (candidate wrld)
(remove-adjacent-duplicates
(merge-sort-term-order
(append (access candidate candidate :changed-vars)
; The following line was changed after Version_3.0.1. It seems like a correct
; change, but we'll leave this comment here until Ruben Gamboa (ACL2(r) author)
; checks this change.
(measured-variables candidate wrld)))))
#+:non-standard-analysis
(defun trap-non-standard-vector (cl-set candidate accum-cl wrld)
(trap-non-standard-vector-aux cl-set accum-cl
(non-standard-vector-check
(non-standard-induction-vars
candidate wrld)
nil)
wrld))
(defun induct (forcing-round pool-lst cl-set hint-settings pspv wrld ctx state)
; We take a set of clauses, cl-set, and return four values. The first
; is either the signal 'lose (meaning we could find no induction to do
; and have explained that to the user) or 'continue, meaning we're
; going to use induction. The second value is a list of clauses,
; representing the induction base cases and steps. The last two
; things are new values for pspv and state. We modify pspv to store
; the induction-hyp-terms and induction-concl-terms for the
; simplifier.
; The clause set we explore to collect the induction candidates,
; x-cl-set, is not necessarily cl-set. If the value, v, of :induct in
; the hint-settings is non-nil and non-*t*, then we explore the clause
; set {{v}} for candidates.
(let ((cl-set (remove-guard-holders-lst-lst cl-set))
(pool-name
(tilde-@-pool-name-phrase forcing-round pool-lst))
(induct-hint-val
(let ((induct-hint-val0
(cdr (assoc-eq :induct hint-settings))))
(and induct-hint-val0
(remove-guard-holders induct-hint-val0)))))
(mv-let
(erp new-pspv state)
(load-hint-settings-into-pspv
nil
(if induct-hint-val
(delete-assoc-eq :induct hint-settings)
hint-settings)
pspv nil wrld ctx state)
(cond
(erp (mv 'lose nil pspv state))
(t
(let* ((candidates
(get-induction-cands-from-cl-set
(select-x-cl-set cl-set induct-hint-val)
new-pspv wrld state))
(flushed-candidates
(m&m candidates 'flush-candidates))
; In nqthm we flushed and merged at the same time. However, flushing
; is a mate and merge function that has the distributive and non-preclusion
; properties and hence can be done with a simple m&m. Merging on the other
; hand is preclusive and so we wait and run m&m-over-powerset to do
; that. In nqthm, we did preclusive merging with m&m (then called
; TRANSITIVE-CLOSURE) and just didn't worry about the fact that we
; messed up some potential merges by earlier merges. Of course, the
; powerset computation is so expensive for large sets that we can't
; just go into it blindly, so we don't use the m&m-over-powerset to do
; flushing and merging at the same time. Flushing eliminates duplicates
; and subsumed inductions and thus shrinks the set as much as we know how.
(merged-candidates
(cond ((< (length flushed-candidates) 10)
(m&m-over-powerset flushed-candidates 'merge-candidates))
(t (m&m flushed-candidates 'merge-candidates))))
; Note: We really respect powerset. If the set we're trying to merge
; has more than 10 things in it -- an arbitrary choice at the time of
; this writing -- we just do the m&m instead, which causes us to miss
; some merges because we only use each candidate once and merging
; early merges can prevent later ones.
(unvetoed-candidates
(compute-vetoes merged-candidates wrld))
(complicated-candidates
(maximal-elements unvetoed-candidates 'induction-complexity
wrld))
(high-scoring-candidates
(maximal-elements complicated-candidates 'score wrld))
(winning-candidate (car high-scoring-candidates)))
(cond
(winning-candidate
(mv-let
(erp candidate-ttree state)
(accumulate-ttree-and-step-limit-into-state
(access candidate winning-candidate :ttree)
:skip
state)
(declare (ignore erp))
(let* (
; First, we estimate the size of the answer if we persist in using cl-set.
(estimated-size
(induction-formula-size cl-set
(access candidate
winning-candidate
:tests-and-alists-lst)))
; Next we create clauses, the set of clauses we wish to prove.
; Observe that if the estimated size is greater than
; *maximum-induct-size* we squeeze the cl-set into the form {{p}},
; where p is a single term. This eliminates the combinatoric
; explosion at the expense of making the rest of the theorem prover
; suffer through opening things back up. The idea, however, is that
; it is better to give the user something to look at, so he sees the
; problem blowing up in front of him in rewrite, than to just
; disappear into induction and never come out. We have seen simple
; cases where failed guard conjectures would have led to inductions
; containing thousands of cases had induct been allowed to compute
; them out.
(clauses0
(induction-formula
(cond ((> estimated-size *maximum-induct-size*)
(list (list (termify-clause-set cl-set))))
(t cl-set))
(access candidate winning-candidate
:tests-and-alists-lst)))
(clauses1
#+:non-standard-analysis
(trap-non-standard-vector cl-set
winning-candidate
clauses0
wrld)
#-:non-standard-analysis
clauses0)
(clauses
(cond ((> estimated-size *maximum-induct-size*)
clauses1)
(t (remove-trivial-clauses clauses1 wrld))))
; Now we inform the simplifier of this induction and store the ttree of
; the winning candidate into the tag-tree of the pspv.
(newer-pspv
(inform-simplify
(access candidate winning-candidate :tests-and-alists-lst)
(add-to-set-equal
(access candidate winning-candidate
:xinduction-term)
(access candidate winning-candidate :xother-terms))
(change prove-spec-var new-pspv
:tag-tree
(cons-tag-trees
candidate-ttree
(access prove-spec-var new-pspv :tag-tree))))))
; Now we print out the induct message.
(let ((state
(io? prove nil state
(wrld clauses estimated-size winning-candidate
high-scoring-candidates complicated-candidates
unvetoed-candidates merged-candidates
flushed-candidates candidates induct-hint-val
cl-set forcing-round pool-lst)
(induct-msg/continue
pool-lst
forcing-round
cl-set
induct-hint-val
(length candidates)
(length flushed-candidates)
(length merged-candidates)
(length unvetoed-candidates)
(length complicated-candidates)
(length high-scoring-candidates)
winning-candidate
estimated-size
clauses
wrld
state))))
(mv 'continue
clauses
newer-pspv
state)))))
(t
; Otherwise, we report our failure to find an induction and return the
; 'lose signal.
(pprogn (io? prove nil state
(induct-hint-val pool-name new-pspv)
(induct-msg/lose pool-name induct-hint-val new-pspv
state))
(mv 'lose nil pspv state))))))))))
; We now define the elimination of irrelevance. Logically this ought
; to be defined when the other processors are defined. But to
; partition the literals of the clause by variables we use m&m, which
; is not defined until induction. We could have moved m&m-apply back
; into the earlier processors, but that would require moving about a
; third of induction back there. So we have just put all of
; irrelevance elimination here.
(defun pair-vars-with-lits (cl)
; We pair each lit of clause cl with its variables. The variables are
; in the car of the pair, the singleton set containing the lit is in
; the cdr.
(cond ((null cl) nil)
(t (cons (cons (all-vars (car cl)) (list (car cl)))
(pair-vars-with-lits (cdr cl))))))
(mutual-recursion
(defun ffnnames-subsetp (term lst)
; Collect the ffnames in term and say whether it is a subset of lst.
; We don't consider fnnames of constants, e.g., the cons of '(a b).
(cond ((variablep term) t)
((fquotep term) t)
((flambda-applicationp term)
(and (ffnnames-subsetp-listp (fargs term) lst)
(ffnnames-subsetp (lambda-body (ffn-symb term)) lst)))
((member-eq (ffn-symb term) lst)
(ffnnames-subsetp-listp (fargs term) lst))
(t nil)))
(defun ffnnames-subsetp-listp (terms lst)
(cond ((null terms) t)
((ffnnames-subsetp (car terms) lst)
(ffnnames-subsetp-listp (cdr terms) lst))
(t nil)))
)
;; Historical Comment from Ruben Gamboa:
;; I added realp and complexp to the list of function names
;; simplification can decide.
(defun probably-not-validp (cl)
; Cl is a clause that is a subset of some clause, cl2, that has survived
; simplification. We are considering whether cl seems useless in proving cl2;
; if so, we return t. In particular, we return t if we think there is an
; instantiation of cl that makes each literal false.
; We have two trivial heuristics. One is to detect whether the only function
; symbols in cl are ones that we think make up a fragment of the theory that
; simplification can decide. The other heuristic is to bet that any cl
; consisting of a single literal which is of the form (fn v1 ... vn) or (not
; (fn v1 ... vn)), where the vi are distinct variables, is probably not valid.
; We elaborate a bit. For eliminating irrelevance, we view a clause as
; (forall x y)(p(x) \/ q(y))
; where p(x) is a possibly irrelevant literal (or set of literals, but we focus
; here on the case of a single literal) and q(y) is the disjunction of the
; other literals. In general, of course, each of these terms may have several
; free variables; but even in general, in order for p(x) to be a candidate for
; irrelevance, its set of variables must be disjoint from the set of variables
; in q. In that case the clause is logically equivalent to the following.
; (forall x)p(x) \/ (forall y)q(y)
; We'd like to ignore one of those disjuncts when choosing an induction
; (actually q could itself be a disjunction on which we recur); but which one?
; If p(x) is probably not valid then we consider it reasonable to ignore p(x) in
; the hope that q(y) may be valid, and indeed provable by ACL2.
; See also the Essay on Alternate Heuristics for Eliminate-Irrelevance.
(or (ffnnames-subsetp-listp cl '(not consp integerp rationalp
#+:non-standard-analysis realp
acl2-numberp
true-listp complex-rationalp
#+:non-standard-analysis complexp
stringp characterp
symbolp cons car cdr equal
binary-+ unary-- < apply))
(case-match cl
((('not (& . args)))
; To understand why we require args to be non-nil, see the Essay on Alternate
; Heuristics for Eliminate-Irrelevance.
(and args ; do not drop zero-ary call (see above)
(all-variablep args)
(no-duplicatesp-eq args)))
(((& . args))
(and args ; do not drop zero-ary call (see above)
(all-variablep args)
(no-duplicatesp-eq args)))
(& nil))))
(defun irrelevant-lits (alist)
; Alist is an alist that associates a set of literals with each key. The keys
; are irrelevant. We consider each set of literals and decide if it is
; probably not valid. If so we consider it irrelevant. We return the
; concatenation of all the irrelevant literal sets.
(cond ((null alist) nil)
((probably-not-validp (cdar alist))
(append (cdar alist) (irrelevant-lits (cdr alist))))
(t (irrelevant-lits (cdr alist)))))
(defun eliminate-irrelevance-clause (cl hist pspv wrld state)
; A standard clause processor of the waterfall.
; We return 4 values. The first is a signal that is either 'hit, or
; 'miss. When the signal is 'miss, the other 3 values are irrelevant.
; When the signal is 'hit, the second result is the list of new
; clauses, the third is a ttree that will become that component of the
; history-entry for this elimination, and the fourth is an
; unmodified pspv. (We return the fourth thing to adhere to the
; convention used by all clause processors in the waterfall (q.v.).)
; Essay on Alternate Heuristics for Eliminate-Irrelevance
; The algorithm for dropping "irrelevant" literals is based on first
; partitioning the literals of a clause into components with respect to the
; symmetric binary relation defined by: two literals are related if and only if
; they share at least one free variable. We consider two ways for a component
; to be irrelevant: either (A) its function symbols are all from among a small
; fixed set of primitives, or else (B) the component has a single literal whose
; atom is the application of a function symbol to distinct variables.
; Criterion B, however, is somewhat problematic, and below we discuss
; variations of it that we have considered. (See function probably-not-validp
; for relevant code.)
; Through Version_7.2, Criterion B was exactly as stated above. However, we
; encountered an unfortunate aspect of that heuristic, which is illustrated by
; the following example (which is simpler than the one actually encountered,
; but is similar in spirit). The THM below failed to prove in Version_7.2.
; (encapsulate
; ((p () t)
; (my-app (x y) t))
; (local (defun p () t))
; (local (defun my-app (x y) (append x y)))
; (defthm my-app-def
; (implies (p)
; (equal (my-app x y)
; (if (consp x)
; (cons (car x) (my-app (cdr x) y))
; y)))
; :rule-classes ((:definition
; :controller-alist ((my-app t nil))))))
;
; (defun rev (x)
; (if (consp x)
; (my-app (rev (cdr x))
; (cons (car x) nil))
; nil))
;
; (thm (implies (and (p)
; (true-listp x))
; (equal (rev (rev x)) x)))
; The problem was that before entering a sub-induction, the hypothesis (P) --
; that is, the literal (NOT (P)) -- was dropped. Here is the relevant portion
; of a log using Version_7.2.
; Subgoal *1/2'5'
; (IMPLIES (AND (P) (TRUE-LISTP X2))
; (EQUAL (REV (MY-APP RV (LIST X1)))
; (CONS X1 (REV RV)))).
;
; We suspect that the terms (TRUE-LISTP X2) and (P) are irrelevant to
; the truth of this conjecture and throw them out. We will thus try
; to prove
;
; Subgoal *1/2'6'
; (EQUAL (REV (MY-APP RV (LIST X1)))
; (CONS X1 (REV RV))).
;
; Name the formula above *1.1.
; Since the exported defthm above requires (P) in order to expand MY-APP, the
; goal displayed immediately above isn't a theorem. So we desired a
; modification of the Criterion B above, on components, that would no longer
; drop (P).
; Our initial solution was a bit elaborate. In essence, it maintained a world
; global whose value is an alist that identifies "never irrelevant" function
; symbols. For a rewrite rule, if a hypothesis and the left-hand side had
; disjoint sets of free variables, and the hypothesis was the application of
; some function symbol F to distinct variables, then F was identified as "never
; irrelevant". We actually went a bit further, by associating a "parity" with
; each such function symbol, both because the hypothesis might actually be (NOT
; (F ...)) and because we allowed the left-hand side to contribute. The
; "parity" could be t or nil, or even :both (to represent both parities). We
; extended this world global not only for rewrite rules but also for rules of
; class :definition, :forward-chaining, :linear, and :type-prescription.
; That seemed to work well: it solved our original problem without noticeably
; slowing down the regression suite or even the time for the expensive form
; (include-book "doc/top" :dir :system).
; We then presented this change in the UT Austin ACL2 seminar, and a sequence
; of events caused us to change our heuristics again.
; (1) During that talk, we stressed the importance of dropping irrelevant
; literals so that an unsuitable induction isn't selected. Marijn Heule
; thus made the intriguing suggestion of keeping the literals and simply
; ignoring them in our induction heuristics.
;
; (2) We tried such a change. Our implementation actually caused
; eliminate-irrelevance-clause to hide the irrelevant literals rather
; then to delete then; then, induction would unhide them immediately
; after choosing an induction scheme.
;
; (3) The regression exhibited failures, however, because subsumption was no
; longer succeeding in cases where it had previously -- a goal was no
; longer subsumed by a previous sibling, but was subsumed by the original
; goal, causing the proof to abort immediately. (See below for details.)
;
; (4) So we decided to drop literals once again, rather than merely to hide
; them.
;
; (5) But on further reflection, it seemed a bit far-fetched that a
; hypothesis (P1 X) could be relevant to simplifying (P2 Y Z) in the way
; shown above that (P) can be relevant to simplifying (P2 Y Z). We can
; construct an example; but we think such examples are likely to be rare.
; The failures due to lack of subsumption led us to be nervous about
; keeping literals that Criterion B would otherwise delete. So we
; decided on a very simple modification of Criterion B: only drop
; applications of functions to one or more variables. This very limited
; case of keeping a literal seems unlikely to interfere with subsumption,
; since that literal could typically be reasonably expected to occur in
; all goals that are stable under simplification.
; Returning to (3) above, here is how subsumption failed for lemma perm-del in
; community book books/models/jvm/m5/perm.lisp, when we merely applied HIDE to
; literals rather than deleting them. In the failed proof, we see the
; following.
; Subgoal *1.1/4'''
; (IMPLIES (AND (NOT (HIDE (CONSP X2)))
; (NOT (EQUAL A X1))
; (MEM X1 Y)
; (NOT (HIDE (CONSP DL))))
; (MEM X1 (DEL A Y))).
;
; Name the formula above *1.1.1.
; Then later we see:
; So we now return to *1.1.2, which is
;
; (IMPLIES (AND (NOT (PERM (DEL X3 X4) (DEL X3 DL0)))
; (NOT (EQUAL X3 X1))
; (MEM X1 Y)
; (MEM X3 DL)
; (PERM X4 DL0))
; (MEM X1 (DEL X3 Y))).
; In Version_7.2 and also currently, the terms with HIDE in the first goal are
; simply gone; so the first goal subsumes the second goal under the
; substitution mapping A to X3. However, with the first goal as shown above
; (from our experiment in hiding irrelevant literals), subsumption fails
; because the hypothesis (NOT (HIDE (CONSP X2))) -- that is, the literal (HIDE
; (CONSP X2)) -- is not present in the second goal.
(declare (ignore hist wrld state))
(cond
((not (assoc-eq 'being-proved-by-induction
(access prove-spec-var pspv :pool)))
(mv 'miss nil nil nil))
(t (let* ((partitioning (m&m (pair-vars-with-lits cl)
'intersectp-eq/union-equal))
(irrelevant-lits (irrelevant-lits partitioning)))
(cond ((null irrelevant-lits)
(mv 'miss nil nil nil))
(t (mv 'hit
(list (set-difference-equal cl irrelevant-lits))
(add-to-tag-tree!
'irrelevant-lits irrelevant-lits
(add-to-tag-tree!
'clause cl nil))
pspv)))))))
(defun eliminate-irrelevance-clause-msg1 (signal clauses ttree pspv state)
; The arguments to this function are the standard ones for an output
; function in the waterfall. See the discussion of the waterfall.
(declare (ignore signal pspv clauses))
(let* ((lits (tagged-object 'irrelevant-lits ttree))
(clause (tagged-object 'clause ttree))
(concl (car (last clause))))
(cond
((equal (length lits)
(length clause))
(fms "We suspect that this conjecture is not a theorem. We ~
might as well be trying to prove~|"
nil
(proofs-co state)
state
(term-evisc-tuple nil state)))
(t
(let ((iterms (cond
((member-equal concl lits)
(append
(dumb-negate-lit-lst
(remove1-equal concl lits))
(list concl)))
(t (dumb-negate-lit-lst lits)))))
(fms "We suspect that the term~#0~[ ~*1 is~/s ~*1 are~] irrelevant to ~
the truth of this conjecture and throw ~#0~[it~/them~] out. We ~
will thus try to prove~|"
(list
(cons #\0 iterms)
(cons #\1 (tilde-*-untranslate-lst-phrase iterms t (w state))))
(proofs-co state)
state
(term-evisc-tuple nil state)))))))
|