/usr/lib/python3/dist-packages/xlrd/xldate.py is in python3-xlrd 1.0.0-1.
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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 | # -*- coding: cp1252 -*-
# No part of the content of this file was derived from the works of David Giffin.
##
# <p>Copyright � 2005-2008 Stephen John Machin, Lingfo Pty Ltd</p>
# <p>This module is part of the xlrd package, which is released under a BSD-style licence.</p>
#
# <p>Provides function(s) for dealing with Microsoft Excel � dates.</p>
##
# 2008-10-18 SJM Fix bug in xldate_from_date_tuple (affected some years after 2099)
# The conversion from days to (year, month, day) starts with
# an integral "julian day number" aka JDN.
# FWIW, JDN 0 corresponds to noon on Monday November 24 in Gregorian year -4713.
# More importantly:
# Noon on Gregorian 1900-03-01 (day 61 in the 1900-based system) is JDN 2415080.0
# Noon on Gregorian 1904-01-02 (day 1 in the 1904-based system) is JDN 2416482.0
import datetime
_JDN_delta = (2415080 - 61, 2416482 - 1)
assert _JDN_delta[1] - _JDN_delta[0] == 1462
# Pre-calculate the datetime epochs for efficiency.
epoch_1904 = datetime.datetime(1904, 1, 1)
epoch_1900 = datetime.datetime(1899, 12, 31)
epoch_1900_minus_1 = datetime.datetime(1899, 12, 30)
class XLDateError(ValueError): pass
class XLDateNegative(XLDateError): pass
class XLDateAmbiguous(XLDateError): pass
class XLDateTooLarge(XLDateError): pass
class XLDateBadDatemode(XLDateError): pass
class XLDateBadTuple(XLDateError): pass
_XLDAYS_TOO_LARGE = (2958466, 2958466 - 1462) # This is equivalent to 10000-01-01
##
# Convert an Excel number (presumed to represent a date, a datetime or a time) into
# a tuple suitable for feeding to datetime or mx.DateTime constructors.
# @param xldate The Excel number
# @param datemode 0: 1900-based, 1: 1904-based.
# <br>WARNING: when using this function to
# interpret the contents of a workbook, you should pass in the Book.datemode
# attribute of that workbook. Whether
# the workbook has ever been anywhere near a Macintosh is irrelevant.
# @return Gregorian (year, month, day, hour, minute, nearest_second).
# <br>Special case: if 0.0 <= xldate < 1.0, it is assumed to represent a time;
# (0, 0, 0, hour, minute, second) will be returned.
# <br>Note: 1904-01-01 is not regarded as a valid date in the datemode 1 system; its "serial number"
# is zero.
# @throws XLDateNegative xldate < 0.00
# @throws XLDateAmbiguous The 1900 leap-year problem (datemode == 0 and 1.0 <= xldate < 61.0)
# @throws XLDateTooLarge Gregorian year 10000 or later
# @throws XLDateBadDatemode datemode arg is neither 0 nor 1
# @throws XLDateError Covers the 4 specific errors
def xldate_as_tuple(xldate, datemode):
if datemode not in (0, 1):
raise XLDateBadDatemode(datemode)
if xldate == 0.00:
return (0, 0, 0, 0, 0, 0)
if xldate < 0.00:
raise XLDateNegative(xldate)
xldays = int(xldate)
frac = xldate - xldays
seconds = int(round(frac * 86400.0))
assert 0 <= seconds <= 86400
if seconds == 86400:
hour = minute = second = 0
xldays += 1
else:
# second = seconds % 60; minutes = seconds // 60
minutes, second = divmod(seconds, 60)
# minute = minutes % 60; hour = minutes // 60
hour, minute = divmod(minutes, 60)
if xldays >= _XLDAYS_TOO_LARGE[datemode]:
raise XLDateTooLarge(xldate)
if xldays == 0:
return (0, 0, 0, hour, minute, second)
if xldays < 61 and datemode == 0:
raise XLDateAmbiguous(xldate)
jdn = xldays + _JDN_delta[datemode]
yreg = ((((jdn * 4 + 274277) // 146097) * 3 // 4) + jdn + 1363) * 4 + 3
mp = ((yreg % 1461) // 4) * 535 + 333
d = ((mp % 16384) // 535) + 1
# mp /= 16384
mp >>= 14
if mp >= 10:
return ((yreg // 1461) - 4715, mp - 9, d, hour, minute, second)
else:
return ((yreg // 1461) - 4716, mp + 3, d, hour, minute, second)
##
# Convert an Excel date/time number into a datetime.datetime object.
#
# @param xldate The Excel number
# @param datemode 0: 1900-based, 1: 1904-based.
#
# @return a datetime.datetime() object.
#
def xldate_as_datetime(xldate, datemode):
"""Convert an Excel date/time number into a datetime.datetime object."""
# Set the epoch based on the 1900/1904 datemode.
if datemode:
epoch = epoch_1904
else:
if xldate < 60:
epoch = epoch_1900
else:
# Workaround Excel 1900 leap year bug by adjusting the epoch.
epoch = epoch_1900_minus_1
# The integer part of the Excel date stores the number of days since
# the epoch and the fractional part stores the percentage of the day.
days = int(xldate)
fraction = xldate - days
# Get the the integer and decimal seconds in Excel's millisecond resolution.
seconds = int(round(fraction * 86400000.0))
seconds, milliseconds = divmod(seconds, 1000)
return epoch + datetime.timedelta(days, seconds, 0, milliseconds)
# === conversions from date/time to xl numbers
def _leap(y):
if y % 4: return 0
if y % 100: return 1
if y % 400: return 0
return 1
_days_in_month = (None, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)
##
# Convert a date tuple (year, month, day) to an Excel date.
# @param year Gregorian year.
# @param month 1 <= month <= 12
# @param day 1 <= day <= last day of that (year, month)
# @param datemode 0: 1900-based, 1: 1904-based.
# @throws XLDateAmbiguous The 1900 leap-year problem (datemode == 0 and 1.0 <= xldate < 61.0)
# @throws XLDateBadDatemode datemode arg is neither 0 nor 1
# @throws XLDateBadTuple (year, month, day) is too early/late or has invalid component(s)
# @throws XLDateError Covers the specific errors
def xldate_from_date_tuple(date_tuple, datemode):
"""Create an excel date from a tuple of (year, month, day)"""
year, month, day = date_tuple
if datemode not in (0, 1):
raise XLDateBadDatemode(datemode)
if year == 0 and month == 0 and day == 0:
return 0.00
if not (1900 <= year <= 9999):
raise XLDateBadTuple("Invalid year: %r" % ((year, month, day),))
if not (1 <= month <= 12):
raise XLDateBadTuple("Invalid month: %r" % ((year, month, day),))
if day < 1 \
or (day > _days_in_month[month] and not(day == 29 and month == 2 and _leap(year))):
raise XLDateBadTuple("Invalid day: %r" % ((year, month, day),))
Yp = year + 4716
M = month
if M <= 2:
Yp = Yp - 1
Mp = M + 9
else:
Mp = M - 3
jdn = (1461 * Yp // 4) + ((979 * Mp + 16) // 32) + \
day - 1364 - (((Yp + 184) // 100) * 3 // 4)
xldays = jdn - _JDN_delta[datemode]
if xldays <= 0:
raise XLDateBadTuple("Invalid (year, month, day): %r" % ((year, month, day),))
if xldays < 61 and datemode == 0:
raise XLDateAmbiguous("Before 1900-03-01: %r" % ((year, month, day),))
return float(xldays)
##
# Convert a time tuple (hour, minute, second) to an Excel "date" value (fraction of a day).
# @param hour 0 <= hour < 24
# @param minute 0 <= minute < 60
# @param second 0 <= second < 60
# @throws XLDateBadTuple Out-of-range hour, minute, or second
def xldate_from_time_tuple(time_tuple):
"""Create an excel date from a tuple of (hour, minute, second)"""
hour, minute, second = time_tuple
if 0 <= hour < 24 and 0 <= minute < 60 and 0 <= second < 60:
return ((second / 60.0 + minute) / 60.0 + hour) / 24.0
raise XLDateBadTuple("Invalid (hour, minute, second): %r" % ((hour, minute, second),))
##
# Convert a datetime tuple (year, month, day, hour, minute, second) to an Excel date value.
# For more details, refer to other xldate_from_*_tuple functions.
# @param datetime_tuple (year, month, day, hour, minute, second)
# @param datemode 0: 1900-based, 1: 1904-based.
def xldate_from_datetime_tuple(datetime_tuple, datemode):
return (
xldate_from_date_tuple(datetime_tuple[:3], datemode)
+
xldate_from_time_tuple(datetime_tuple[3:])
)
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