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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 | % We have a 3-gallon jug and a 4-gallon jug, both empty, and a well.
% Our goal is to have exactly 2 gallons in the 4-gallon jug. We
% can fill a jug from the well, empty a jug onto the ground, and
% carefully pour water from one jug into the other.
%
% J(m, n) is the state in which the 3-gallon jug contains m gallons,
% and the 4-gallon jug contains n gallons.
%
% Note that there is no binary "minus" operation; we write "x+ -y"
% instead of "x-y".
set(production).
formulas(usable).
J(x, y) -> J(3, y). % fill the 3-gallon jug
J(x, y) -> J(0, y). % empty the 3-gallon jug
J(x, y) -> J(x, 4). % fill the 4-gallon jug
J(x, y) -> J(x, 0). % empty the 4-gallon jug
J(x, y) & (x+y <= 4) -> J(0, y+x). % empty the small jug into the big jug
J(x, y) & (x+y > 4) -> J(x + -(4+ -y), 4). % small -> big, until full
J(x, y) & (x+y <= 3) -> J(x+y, 0). % empty the big jug into the small jug
J(x, y) & (x+y > 3) -> J(3, y + - (3+ -x)). % big -> small, until full
end_of_list.
formulas(assumptions).
J(0, 0). % initial state: both jugs empty
end_of_list.
formulas(goals).
exists x J(x, 2). % goal state: 4-gallon jug containing 2 gallons
end_of_list.
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